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Anna11 [10]
3 years ago
15

What is the rule when reflecting across the line y = x

Mathematics
1 answer:
blsea [12.9K]3 years ago
3 0

Answer: switch the x and y values of the coordinates

(x, y) —> (y, x)

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For a cone, if the radius was quadrupled and the slant height was reduced to 1/6 of its original size what would be the formula
Paladinen [302]
Let r be the radius of the cone's base and \ell the slant height.

The surface area of a cone is

A=\pi r^2+\pi r\ell

If the radius is quadrupled (r\to4r) and the slant height scaled by a factor of \dfrac16, then the new area is

A=\pi(4r)^2+\pi (4r)\left(\dfrac\ell6\right)
A=16\pi r^2+\dfrac23\pi r\ell
7 0
3 years ago
12foot 11incher+11foot 3 incher​
mash [69]

Answer:

24feet 1 inches

Step-by-step explanation:

4 0
3 years ago
Suppose John is a high school statistics teacher who believes that scoring higher on homework assignments leads to higher test s
EleoNora [17]

Answer:

A. R2 = 0.6724, meaning 67.24% of the total variation in test scores can be explained by the least‑squares regression line.

Step-by-step explanation:

John is predicting test scores of students on the basis of their home work averages and he get the following regression equation

y=0.2 x +82.

Here, dependent variable y is the test scores and independent variable x is home averages because test scores are predicted on the basis of home work averages.

The coefficient of determination R² indicates the explained variability of dependent variable due to its linear relationship with independent variable.

We are given that correlation coefficient r= 0.82.

coefficient of determination R²=0.82²=0.6724 or 67.24%.

Thus, we can say that 67.24% of total variability in test scores is explained by its linear relationship with homework averages.

Also, we can say that, R2 = 0.6724, meaning 67.24% of the total variation in test scores can be explained by the least‑squares regression line.

3 0
3 years ago
What is |5+3w|/-2 -1
madreJ [45]

Answer:

Step-by-step explanation:

Your maths problem

|

5

+

3

|

−

2

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1

5 0
3 years ago
How do you solve: 4 + |k + 1| <15
Viktor [21]
4+|k+1|<15
-4           -4      15-4=11
|k+1|<11         |k+1|=k+1
k+1<11
  -1    -1
k<10
6 0
3 years ago
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