13.82 g / 180.16 g/mol = .07671 moles
.07671 moles / (86.18 g / 1000 g/kg) = .8901 molal
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This problem is providing the atmospheric pressure at 2000 m altitude which is 560. mmHg and asks for this pressure in units of atmospheres, which after doing the calculations, the result is 0.737atm.
<h3>Atmospheric pressure:</h3><h3 />
In this case, we can firstly define the concept of atmospheric pressure, also known as barometric pressure, as that pressure exerted by a column of air over a specific point in space at a defined altitude.
<h3>Units conversion in pressure:</h3><h3 />
In order to get the correct conversion, we use the following equivalence statement relating mercury millimeters and atmospheres:
760 mmHg = 1 atm
Hence, the required conversion turns out to be:

Learn more about atmospheric pressure: brainly.com/question/1393320
K2CO3 can be thought to contain 6 atoms (2 K, 1 C, 3O).
If you are given grams of K2CO3 you can divide by the molar mass to get to moles and then multiply by Avogadro's number.