Answer:
D) 6
Explanation:
The balanced equation would be:
6Li + N2 -> 2Li3N
Answer:
The compound with the correct formula is;
A. MNO₃
Explanation:
The number of oxidation states in the metal, M = One oxidation state
The formula of the compound formed by the metal, M = MHCO₃
We note that the ion HCO₃⁻, known as hydrogen carbonate has an oxidation number of -1
Similarly nitrate, NO₃⁻ has an oxidation number of -1, therefore, the metal M can form similar compound formed with HCO₃⁻ with nitrate, and we have;
The possible compounds formed by the metal 'M' includes MHCO₃ and MNO₃.
The three ways that an atom can fulfill this goal is to give away electrons, take an electron, and share electrons.
Answer:
81.97 g of NaAl(OH)₄
Solution:
The reaction for the preparation of Sodium Aluminate from Aluminium Metal and NaOH is as follow,
2 NaOH + 2 Al + 6 H₂O → 2 NaAl(OH)₄ + 3 H₂
According to this equation,
2 Moles of NaOH produces = 163.94 g (2 mole) of NaAl(OH)₄
So,
1 Mole of NaOH will produce = X g of NaAl(OH)₄
Solving for X,
X = (1 mol × 163.94 g) ÷ 2 mol
X = 81.97 g of NaAl(OH)₄