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lorasvet [3.4K]
3 years ago
15

What is the iupac name of this structure?

Chemistry
1 answer:
alexgriva [62]3 years ago
5 0

Answer:

3–ethyl–4–methylhexane.

Explanation:

To name the above compound, do the following:

1. Determine the functional group of the compound.

2. Locate the longest continuous carbon chain. This gives the parent name of the compound.

3. Identify the substituent group attached to the compound.

4. Give the substituent the lowest possible count.

5. Combine the above to name the compound.

Now, we shall name the compound given in the question above as follow:

1. The compound contains only single bond. Therefore, the compound belong to the alkane family.

2. The longest continuous carbon chain is 6 i.e hexane.

3. The substituent group attached are:

i. Methyl, CH3.

ii. Ethyl, CH2CH3.

4. we shall name the substituents alphabetically i.e ethly will come before methyl. Therefore,

Ethyl is located at carbon 3.

Methy is located at carbon 4.

5. Therefore, the name of the compound is:

3–ethyl–4–methylhexane.

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Which option states the principle behind the law of conservation of mass and the law of conservation of energy?
jeka94

Answer:

A

Explanation:

The law of conservation of mass states that matter can never be created nor destroyed but can be converted from one form to another.

The law of conservation of energy posits that energy cannot be created nor destroyed but can be converted from one form to another.

These laws are the basic laws of existence. Although the laws have been adjusted, they still form the basic principle behind several scientific laws and are responsible for a whole lot of scientific advancements.

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7 0
3 years ago
When (R)-2-chloro-3-methylbutane is treated with potassium tert-butoxide, a monosubstituted alkene is obtained. When this alkene
Aleks [24]

Answer:

See explanation and image attached

Explanation:

The reaction of (R)-2-chloro-3-methylbutane with potassium tert-butoxide yields a monosubstituted alkene .

Since the base is bulky, the Hoffman product predominates because attack occurs at the less hindered carbon atom to yield the major product as shown.

The alkene reacts with HBr at the secondary carbon atom to yield a carbocation intermediate which is flat and planar. Attack on either face of the carbocation yields a racemic mixture of the (2R) and (2S) products.

Rearrangement of the carbocation to yield a tertiary carbocation gives the 2-bromo-2-methyl butane product as shown in the image attached.

6 0
3 years ago
Me podrían ayudar :((​
Lady bird [3.3K]
Dora is helping you with this
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