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Gekata [30.6K]
2 years ago
13

PLEASE HELP!

Chemistry
2 answers:
fgiga [73]2 years ago
5 0
150/30 = 5
HF1 20/2 = 10
HF2 10/2 = 5
HF3 5/2 = 2.5
HF4 2.5/2 = 1.25
HF5 1.25/2 = 0.625
Answer: 0.63g
NikAS [45]2 years ago
4 0

Answer:  0,63 g

Explanation: During 150 days 5 decays happen. You can write a set

of masses : 20 g ⇒ 10 g after first decay, then 5 g , 2.5 g , 1,25 g

and after fifth decay 0.63 g

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The energy required to ionize boron is 801 kJ/mol. You may want to reference (Pages 93 - 98) Section 2.5 while completing this p
earnstyle [38]

Answer:

The frequency is  f =  2,01 * 10^{15} \  Hz

Explanation:

From the question we are told that

   The energy required to ionize boron is E_b  =  801 KJ/mol

Generally the ionization energy of boron pre atom is mathematically represented as

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Here  N_A is the Avogadro's constant with value N_A  =  6.022*10^{23}

So

      E_a  =  \frac{801}{6.022*10^{23}}

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Generally the energy required to liberate one electron from an atom is equivalent to the ionization energy per atom and this mathematically represented as

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=>     hf  =  E_a

Here h is the Planks constant with value h = 6.626 *10^{-34}

So

       f =  \frac{1.330 *10^{-18}}{ 6.626 *10^{-34}}

=>      f =  2,01 * 10^{15} \  Hz

8 0
3 years ago
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Answer:

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Explanation:

4 0
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Pls help me out with this question!
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