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Llana [10]
3 years ago
14

The printer prints 16 pages every minute. How many pages are printed in 6 minutes?

Computers and Technology
2 answers:
Olenka [21]3 years ago
7 0

Answer:

96 pages are printed in 6 minutes

dybincka [34]3 years ago
4 0

Answer: 96 pages

Explanation:

If the printer prints 16 pages every 1 min, then just times 16 by 6

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Lelechka [254]
A - they all use microprocessors to compute and store data.
3 0
3 years ago
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In Java, it is possible to create an infinite loop out of while and do loops, but not for-loops. true or false
soldier1979 [14.2K]

Answer:

False is the correct answer for the above question.

Explanation:

  • In java programming language or any other programming language, any loop can be infinite.
  • It is because the infinite loop is called for that loop which is not run in a finite number of times.
  • The loop is used to repeat some lines in a finite number of times. Any loop has three things- first is the initial value which tells the loop to start, The second is the condition check which states when the loop will stop and the third is an operation which directs some variable, so that the condition may be false after some finite amount of time.
  • If the condition will not false in any iteration of the loop, then the loop can proceed for an infinite amount of time.
  • The above-question states that the while loop and do while loop can be infinite which is a true statement.
  • But it also states that the 'for' loop can not be infinite which is not a correct statement which is described above. Hence false is the correct answer to the above question.
8 0
3 years ago
Create the following SQL Server queries that access the Northwind database. Place them in a zip file and place the zip file in t
neonofarm [45]

Answer:

1. SELECT e.EmployeeID, e.FirstName, e.LastName, COUNT(*) as OrderByEmployee FROM Employees e

JOIN Orders o

ON e.EmployeeID = o.EmployeeID

WHERE YEAR(o.OrderDate) = '1996'

GROUP BY e.EmployeeID,e.FirstName,e.LastName

ORDER BY OrderByEmployee DESC

2. SELECT o.OrderID,c.CustomerID, o.OrderDate,SUM((od.Quantity)*

od.UnitPrice - od.Discount)) as TotalCost FROM Orders o

JOIN [Order Details] od

ON od.OrderID = o.OrderID

JOIN Customers c

ON o.CustomerID = c.CustomerID

WHERE (MONTH(OrderDate)= 7 OR MONTH(OrderDate) = 8) and

YEAR(OrderDate) = 1996

GROUP BY o.OrderID,c.CustomerID, o.OrderDate

ORDER BY TotalCost DESC

3. SELECT c.CustomerID, c.CompanyName, c.City, COUNT(o.OrderID) as TotalOrder, SUM(od.Quantity* od.UnitPrice) as TotalOrderAmount FROM Customers c

JOIN Orders o

ON o.CustomerID = c.CustomerID

JOIN [Order Details] od

ON od.OrderID = o.OrderID

WHERE c.Country = 'USA'

GROUP BY c.CustomerID, c.CompanyName, c.City

ORDER BY c.City, c.CustomerID

4. SELECT c.CustomerID, c.CompanyName, c.City, COUNT(o.OrderID) as TotalOrder, SUM(od.Quantity* od.UnitPrice) as TotalOrderAmount FROM Customers c

JOIN Orders o

ON o.CustomerID = c.CustomerID

JOIN [Order Details] od

ON od.OrderID = o.OrderID

WHERE c.Country = 'USA'

GROUP BY c.CustomerID, c.CompanyName, c.City

HAVING COUNT(o.OrderID) > 3

ORDER BY c.City, c.CustomerID

5. SELECT p.ProductID, p.ProductName, s.ContactName as SupplierName, MAX(o.OrderDate) as LastOrderDateOfProduct FROM Products p

JOIN Categories c

ON c.CategoryID = p.CategoryID

JOIN Suppliers s

ON s.SupplierID = p.SupplierID

JOIN [Order Details] od

ON od.ProductID = p.ProductID

JOIN Orders o

ON o.OrderID = od.OrderID

where c.CategoryName = 'Grains/Cereals'

GROUP BY p.ProductID, p.ProductName, s.ContactName

ORDER BY SupplierName, p.ProductName

6. SELECT p.ProductID, p.ProductName, Count(DISTINCT c.CustomerID ) as OrderByThisManyDistinctCustomer

FROM Products p

JOIN [Order Details] od

ON od.ProductID = p.ProductID

JOIN Orders o

ON o.OrderID = od.OrderID

JOIN Customers c

ON c.CustomerID = o.CustomerID

where YEAR(o.OrderDate) = 1996

GROUP BY p.ProductID, p.ProductName

Explanation:

The six query statements returns data from the SQL server Northwind database. Note that all the return data are grouped together, this is done with the 'GROUP BY' Sql clause.

8 0
3 years ago
I need an answer and fast What happens if a sequence is out of order?
horsena [70]

Answer:

i would say A

hope i helped <3

Explanation:

4 0
4 years ago
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Programming CRe-type the code and fix any errors. The code should convert non-positive numbers to 1.
LUCKY_DIMON [66]

Answer:

Given

The above lines of code

Required

Rearrange.

The code is re-arrange d as follows;.

#include<iostream>

int main()

{

int userNum;

scanf("%d", &userNum);

if (userNum > 0)

{

printf("Positive.\n");

}

else

{

printf("Non-positive, converting to 1.\n");

userNum = 1;

printf("Final: %d\n", userNum);

}

return 0;

}

When rearranging lines of codes. one has to be mindful of the programming language, the syntax of the language and control structures in the code;

One should take note of the variable declarations and usage

See attachment for .cpp file

Download cpp
5 0
4 years ago
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