Answer:
The function definition for this question can be given as:
Function Definition:
bool isSenior(int x ) //function
{
//function body Or function definition.
//conditional statement
//if statement
if (x >=65)
{
return true; //return value true.
}
else //else statement
{
return false; //return value false.
}
}
Explanation:
In the above function definition firstly we define a function that isSenior. This function return Boolean value that is true or false in this function we pass the value as the parameter in that function we use the if statement that check the pass value is greater then equal to 65. If the condition is true it return true.else it will return false.
Answer:
They acknowledge the source of a quotation, paraphrase, or summary; and (2) They provide explanatory comments that would interrupt the flow of the main text.so its B
Answer:
Recursive solutions can be less efficient than their iterative counterparts
Explanation:
Recursion can be defined or described as a method of solving a problem where the solution depends on solutions to smaller instances of the same problem.
It entails using iteration to ensure that smaller parts of a solution are satisfied towards solving thw overall problem.
Ita major disadvantage seems to be that it seem to be less efficient than their iterative counterparts. This is as a result of concentrating on trying to solve a smaller instances.
Answer:
The statement is as follows:
print("{0:,.1f}".format(number))
Explanation:
Required
Statement to print 1234567.456 as 1,234,567.5
To do this, we make use of the format keyword, and we set the print format in the process.
To round up number to 1 decimal place, we use the following format:
"{0:,.1f}"
To include comma in the thousand place, we simply include a comma sign before the number of decimal place of the output; i.e. before 1
"{0:,.1f}"
So, the print statement is:
print("{0:,.1f}".format(number))
