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3 years ago

Which one of the patterns have the highest pitch?

Computers and Technology

2 answers:

olga nikolaevna [1]3 years ago

5 0

The answer is B because if you see the others none of them have reached to the top except B

fomenos3 years ago

3 0

Answer:

The answers is B

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What activities are the most likely to infect your computer vith a virus? Check all that apply.

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Answer:A,B,E

Explanation:

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4 years ago

Define lan wan & man

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3 years ago

In cyber security, one of the best ways to protect a computer or network is with a strategy called defense in depth. This strate

emmainna [20.7K]

This idea is most closely related to the Layering in terms of how to reduce complexity.

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Defense in depth is a technique used in cybersecurity that is one of the greatest ways to safeguard a computer or network. If one fails, it's likely that another will identify the issue. The approach to simplifying that is most in line with is called layering.

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2 years ago

Read 2 more answers

A computer retail store has 15 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail st

Dima020 [189]

Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

$^nC_r = \frac{n!}{(n-r)!r!}$

Where $n = 15\ and\ r = 4$

$^{15}C_4 = \frac{15!}{(15-4)!4!}$

$^{15}C_4 = \frac{15!}{11!4!}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{32760}{24}$

$^{15}C_4 = 1365$

<em>Hence, there are 1365 ways </em>

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

<em>From the given parameters; 3 out of 15 is detective;</em>

So;

$p = 3/15$

$p = 0.2$

$q = 1 - p$

$q = 1 - 0.2$

$q = 0.8$

Solving further using binomial;

$(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n$

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

$Probability = ^nC_3pq^3$

Substitute 4 for n, 0.2 for p and 0.8 for q

$Probability = ^4C_3 * 0.2 * 0.8^3$

$Probability = \frac{4!}{3!1!} * 0.2 * 0.8^3$

$Probability = 4 * 0.2 * 0.8^3$

$Probability = 0.4096$

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

<em>Probability that at least one is defective + Probability that at none is defective = 1</em>

Probability that none is defective is calculated as thus;

$Probability = q^n$

Substitute 4 for n and 0.8 for q

$Probability = 0.8^4$

$Probability = 0.4096$

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

8 0

3 years ago

Bert started off his working life as a typesetter for a print house. With the advent of new technologies, Bert's job became redu

Inessa [10]

Answer:

Berth's job became redundant because she lacks the computing skills. Perhaps, she has been using manual or analog type writing machine to do her job and was doing it well but with the advent of computer that replaces analog type writer, she will become redundant.

Explanation:

She needs to learn how to use the computer to type and do her job efficiently in the print industry.

5 0

3 years ago

Which one of the patterns have the highest pitch?​

Which one of the patterns have the highest pitch?