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Scorpion4ik [409]
3 years ago
9

2x + 4 / 3 = -8 please help

Mathematics
2 answers:
arsen [322]3 years ago
4 0
X= -14/3 !


hope this helps
Lelechka [254]3 years ago
4 0

Answer:

X= -14/3

Step-by-step explanation:

Subtract \frac{4}{3}  

3

4

​  

 from both sides.

2x=-8-\frac{4}{3}

2x=−8−  

3

4

​  

 

2 Simplify  -8-\frac{4}{3}−8−  

3

4

​  

  to  -\frac{28}{3}−  

3

28

​  

.

2x=-\frac{28}{3}

2x=−  

3

28

​  

 

3 Divide both sides by 22.

x=-\frac{\frac{28}{3}}{2}

x=−  

2

3

28

​  

 

​  

 

4 Simplify  \frac{\frac{28}{3}}{2}  

2

3

28

​  

 

​  

  to  \frac{28}{3\times 2}  

3×2

28

​  

.

x=-\frac{28}{3\times 2}

x=−  

3×2

28

​  

 

5 Simplify  3\times 23×2  to  66.

x=-\frac{28}{6}

x=−  

6

28

​  

 

6 Simplify  \frac{28}{6}  

6

28

​  

  to  \frac{14}{3}  

3

14

​  

.

x=-\frac{14}{3}

x=−  

3

14

​  

 

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5 0
3 years ago
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valentinak56 [21]
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7 0
3 years ago
Read 2 more answers
The sum of two polynomials is 8d5 – 3c3d2 + 5c2d3 – 4cd4 + 9. If one addend is 2d5 – c3d2 + 8cd4 + 1, what is the other addend?
Anit [1.1K]

Answer: The correct option is A.

Step-by-step explanation: We are given a polynomial which is a sum of other 2 polynomials.

We are given the resultant polynomial which is : 8d^5-3c^3d^2+5c^2d^3-4cd^4+9

One of the polynomial which are added up is : 2d^5-c^3d^2+8cd^4+1

Let the other polynomial be 'x'

According to the question:

8d^5-3c^3d^2+5c^2d^3-4cd^4+9=x+(2d^5-c^3d^2+8cd^4+1)

x=8d^5-3c^3d^2+5c^2d^3-4cd^4+9-(2d^5-c^3d^2+8cd^4+1)

Solving the like terms in above equation we get:

x=(8d^5-2d^5)+(-3c^3d^2+c^3d^2)+(5c^2d^3)+(-4cd^4-8cd^4)+(9-1)

x=6d^5-2c^3d^2+5c^2d^3-12cd^4+8

Hence, the correct option is A.

5 0
3 years ago
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Answer:

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3 0
3 years ago
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