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ArbitrLikvidat [17]
3 years ago
6

QUESTION 10

Chemistry
2 answers:
almond37 [142]3 years ago
3 0
A. Niche

a niche is like a role in an ecosystem and the sunflowers role is converting co2 to oxygen and providing shelter
Delicious77 [7]3 years ago
3 0
The answer is a hope this helps
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Write the equations for the preparation of n-butane from
IRINA_888 [86]
A) LiAlH4 b) Ph(3)SnH c)Na in dry ether(Wurtz reaction)
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3 years ago
Name the element that has atom with 4 proton in the nucleus
QveST [7]
The element with 4 protons in the nucleus in Beryllium.
6 0
3 years ago
Read 2 more answers
What is the mass of carbon monoxide (CO) gas if the gas occupies a volume of 4.1 L at 2.0 atm of pressure and -73oC?
Stels [109]

Answer:

1.7

Explanation:

4 0
2 years ago
1) When 2.38g of magnesium is added to 25.0cm of 2.27 M hydrochloric acid, hydrogen gas is released.
Andrej [43]

Answer:

a. HCl.

b. 0.057 g.

c. 1.69 g.

d. 77 %.

Explanation:

Hello!

In this case, since the reaction between magnesium and hydrochloric acid is:

Mg+2HCl\rightarrow MgCl_2+H_2

Whereas there is 1:2 mole ratio between them.

a) Here, we can identify the limiting reactant as that yielded the fewest moles of hydrogen gas product via the 1:1 and 2:1 mole ratios:

n_{H_2}^{by\  HCl}=0.025L*2.27\frac{molHCl}{1L}*\frac{1molH_2}{2molHCl}  =0.0284molH_2\\\\n_{H_2}^{by\  Mg}=2.38gMg*\frac{1molMg}{24.3gMg}*\frac{1molH_2}{1molMg}=0.0979molH_2

Thus, since hydrochloric yields fewer moles of hydrogen than magnesium, we realize it is the limiting reactant.

b) Here, we use the molar mass of gaseous hydrogen (2.02 g/mol) to compute the mass:

m_{H_2}=0.0284molH_2*\frac{2.02gH_2}{1molH_2}=0.057gH_2

c) Here, we compute the mass of magnesium associated with the yielded 0.0248 moles of hydrogen:

m_{Mg}^{reacted}=0.0284molH_2*\frac{1molMg}{1molH_2}*\frac{24.3gMg}{1molMg}  =0.690gMg

Thus, the mass of excess magnesium turns out:

m_{Mg}^{excess}=2.38g-0.690g=1.69gMg

d) Finally, we compute the percent yield, considering 0.044 g is the actual yield and 0.057 g the theoretical yield:

Y=\frac{0.044g}{0.057g} *100\%\\\\Y=77\%

Best regards!

8 0
3 years ago
According to the below equation, how many moles of SO2 are required to generate 1.43×1024 water molecules?
podryga [215]
Make sure the equation is always balanced first. (It is balanced for this question already) 6.022 x 10^23 is Avogadro’s number. In one mole of anything there is always 6.022 x 10^23 molecules, formula units, atoms. For one mol of an element/ compound use molar mass (grams).

Multiply everything on the top = 8.61x10^47
Multiple everything on bottom= 1.20x10^24
Divide top and bottom = 7.15x10^23

Answer: 7.15x10^23 mol SO2
3 0
3 years ago
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