QUESTION 10
2 answers:
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Hello!
First, we can assume the density of water to be 1 g/mL, so the volume of water would be 725 mL. The density of Acetic Acid (Pure) is 1,05 g/mL so 8 grams would represent 7,61 mL
Now we can apply the following conversion factor to calculate the molarity of the solution, using the molar mass of Acetic Acid:
![[CH_3CO_2H]=\frac{8 g_{CH_3CO_2H} }{725 mL + 7,61 mL}* \frac{1000 mL}{1 L}* \frac{1 mol_{CH_3CO_2H} }{60,05 g_{CH_3CO_2H} }](https://tex.z-dn.net/?f=%5BCH_3CO_2H%5D%3D%5Cfrac%7B8%20g_%7BCH_3CO_2H%7D%20%20%7D%7B725%20mL%20%2B%207%2C61%20mL%7D%2A%20%5Cfrac%7B1000%20mL%7D%7B1%20L%7D%2A%20%5Cfrac%7B1%20mol_%7BCH_3CO_2H%7D%20%7D%7B60%2C05%20g_%7BCH_3CO_2H%7D%20%7D)
![[CH_3CO_2H]=0,1818 M](https://tex.z-dn.net/?f=%5BCH_3CO_2H%5D%3D0%2C1818%20M)
So, the concentration of acetic acid would be 0,1818 M
Have a nice day!
First, we can assume the density of water to be 1 g/mL, so the volume of water would be 725 mL. The density of Acetic Acid (Pure) is 1,05 g/mL so 8 grams would represent 7,61 mL
Now we can apply the following conversion factor to calculate the molarity of the solution, using the molar mass of Acetic Acid:
So, the concentration of acetic acid would be 0,1818 M
Have a nice day!
Answer:
122.5 Joule, or 122.5 j
Explanation:
Given,
mass of the object (m) = 5 kg
velocity of the object (v) = 7 m/s
Kinetic energy = × m × v²
Applying the formula:
Kinetic energy = × 5 × 7²
⇒ × 5 × 7 × 7
⇒
⇒ 122.5 Joule, or 122.5 j
Kinetic energy is the energy that an object gains as the result of the motion. It also depends on the mass of the object and force with which the motion is applied. In the given question, the mass of the object is 5 kg and the force of the velocity by which it is moving is 7 m/s.
Answer:
–187.9 J/K
Explanation:
The equation that relates the three quantities is:
where
is the Gibbs free energy
is the change in enthalpy of the reaction
T is the absolute temperature
is the change in entropy
In this reaction we have:
ΔS = –187.9 J/K
ΔH = –198.4 kJ = -198,400 J
T = 297.0 K
So the Gibbs free energy is
However, here we are asked to say what is the entropy of the reaction, which is therefore
ΔS = –187.9 J/K