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2 years ago

According to the arrhenius concept, the

1 answer:

8 0

According to the Arrhenius concept, the strength of an acid depends upon the H⁺ ions furnished by the acid.

<h3>What is the Arrhenius theory of acids?</h3>

According to the Arrhenius theory, acids are those substance which will give H⁺ ion in an aqueous solution.

And acidity of any substance will be calculated by using the pH value which can be calculated as pH = -log[H⁺].

Hydrolysis will not able to define the strength of the acid.
Concentration of the acid is also not valid to define the strength of the acid because all acids will not have H⁺ ion.
Number of moles of the base which are used for neutralization is also not used to define the strength of Arrhenius acid.

Hence H⁺ ions furnished by the acid is used to define the strength of Arrhenius acid.

To know more about Arrhenius acid, visit the below link:

brainly.com/question/1163742

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What is the value of the equilibrium constant at 25 oC for the reaction between the pair: Ag(s) and Ni2+(aq) to give Ni(s) and A

rusak2 [61]

Answer: $3\times 10^{35}$

Explanation:

The balanced chemical equation will be:

$2Ag(s)+Ni^{2+}(aq)\rightarrow 2Ag^{+}(aq)+Ni(s)$

Here Ag undergoes oxidation by loss of electrons, thus act as anode. Nickel undergoes reduction by gain of electrons and thus act as cathode.

$E^0=E^0_{cathode}- E^0_{anode}$

Where both $E^0$ are standard reduction potentials.

$E^0_{[Ag^{+}/Mg]}=+0.80V$

$E^0_{[Ni^{2+}/Ni]}=-0.25V$

$E^0=E^0_{[Ni^{2+}/Ni]}- E^0_{[Ag^{+}/Ag]}$

$E^0=-0.25-(+0.80V)=-1.05V$

The standard emf of a cell is related to Gibbs free energy by following relation:

$\Delta G=-nFE^0$

$\Delta G$ = gibbs free energy

n= no of electrons gained or lost =?

F= faraday's constant

$E^0$ = standard emf

$\Delta G=-2\times 96500\times (-1.05)=202650J$

The Gibbs free energy is related to equilibrium constant by following relation:

$\Delta G=-2.303RTlog K$

R = gas constant = 8.314 J/Kmol

T = temperature in kelvin = $25^0C=25+273=298K$

K = equilibrium constant

$\Delta G=-2.303RTlog K$

$+202650=-2.303\times 8.314\times 298\times logK$

$K=3\times 10^{35}$

Thus the value of the equilibrium constant at $25^0C$ is $3\times 10^{35}$

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3 years ago

Question 3 0 / 1 point How many grams of carbon atoms are present in a sample of C3H8 if there are 4.10 moles of hydrogen atoms

hodyreva [135]

Answer:

18.45 g of C

Explanation:

This is a problem of rules of three:

1 mol of C₃H₈ contains 3 moles of C and 8 moles of H

If 8 moles of H are contained in 1 mol of propane

4.10 moles of H are contained in (4.1 . 1) /8 = 0.5125 moles

Now, If 1 mol of propane contains 3 moles of C

0.5125 moles of propane may contain (0.5125 . 3) / 1 = 1.5375 moles of C

Let's convert the moles to mass:

1.5375 mol . 12 g /mol = 18.45 g

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