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2 years ago

Can you dissolve. 35 moles of potassium permanganate (kmno4) into 500 ml of water? _________ why? / why not?

2 answers:

5 0

We can not dissolve 35 moles of potassium permanganate into 500 ml of water as it produces the solution with higher molarity than water have.

<h3>What is molarity?</h3>

Molarity of any solution is define as the number of moles of solute present in per liter of the solvent as:

M = n/V

The molarity of the solvent, water, is the highest for aqueous solutions and molarity of 1000g of pure water in 1 liter is 55.5M

Given that,

n = moles of potassium permanganate = 35 moles
V = Volume = 500 mL = 500 / 1000 = 0.5 L

On putting values, we get

M = 35/0.5 = 70M

Preparation of this solution is impossible.

Hence, KMnO₄ will not dissolve in the water as it produces solution with higher molarity than water.

To know more about molarity, visit the below link:
brainly.com/question/10608366

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Greeley [361]2 years ago

3 0

Yes, we can dissolve 35 moles of KMnO₄ into 500 mL of water to give a molarity of 70 M

<h3>What is molarity? </h3>

Molarity is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:

Molarity = mole / Volume

<h3>How to determine the molarity </h3>

Mole of KMnO₄ = 35 moles
Volume = 500 mL = 500 / 1000 = 0.5 L

Molarity =?

Molarity = mole / Volume

Molarity = 35 / 0.5

Molarity = 70 M

Learn more about molarity:

brainly.com/question/9468209

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The principal source of sulfur on earth is deposits of free sulfur occurring mainly in volcanically Active regions. The offer wa

aivan3 [116]

Answer:

1.18x10⁸L of SO₂ and 2.36x10⁸L of H₂S

Explanation:

The balanced reaction is:

8SO₂(g) + 16H₂S(g) → 16H₂O(l) + 3S₈(s)

To solve this question we must find the moles of S₈ in 4.50x10⁵kg. With these moles and the reaction we can find the moles of SO₂ needed to react (Twice these moles = Moles Of H₂S needed). Using PV = nRT we can find the volume of the gas required:

<em>Moles S₈ - molar mass: 256.52g/mol-</em>

4.50x10⁵kg = 4.50x10⁸g * (1mol / 256.52g) =

1.75x10⁶ moles S₈

<em>Moles SO₂:</em>

1.75x10⁶ moles S₈ * (8mol SO₂ / 3mol S₈) = 4.68x10⁶ moles SO₂

<em>Moles H₂S:</em>

4.68x10⁶ moles SO₂ * 2 = 9.36x10⁶ moles H₂S

The volume could be obtained as follows:

PV = nRT

V = nRT / P

<em>V is volume in liters</em>

<em>n are moles: 4.68x10⁶ moles SO₂ and 9.36x10⁶ moles H₂S</em>

<em>R is gas constant = 0.082atmL/molK</em>

<em>T is absolute temperature = 22°C + 273.15 = 295.15K</em>

<em>P is pressure = 0.961atm</em>

<em />

Replacing:

Volume SO₂ and H₂S:

4.68x10⁶ moles * 0.082atmL/molK * 295.15K / 0.961atm =

<em>9.36x10⁶ moles H₂S</em> * 0.082atmL/molK * 295.15K / 0.961atm =

5 0

3 years ago

Anyone else board answer for free points

Dovator [93]

You spelled bored wrong lol

3 0

3 years ago

Read 2 more answers

Be sure to answer all parts. one of the most important industrial sources of ethanol is the reaction of steam with ethene derive

lions [1.4K]

Answer: 2.17x10⁻³ atm

Explanation:

First, we must write the balanced chemical equation for the process:

C₂H₄(g) + H₂O(g) ⇌ C₂H₅OH(g)

The chemical reactions that occur in a closed container can reach a state of <u>chemical equilibrium</u> that is characterized because the concentrations of the reactants and products remain constant over time. The <u>equilibrium constant</u> of a chemical reaction is the value of its reaction quotient in chemical equilibrium.

The equilibrium constant (K) is expressed as <u>the ratio between the molar concentrations (mol/L) of reactants and products.</u> Its value in a chemical reaction depends on the temperature, so it must always be specified.

<u>We will use the the equilibrium constant Kc of the reaction to calculate partial pressure of ethene.</u> The constant Kc for the above reaction is,

Kc = $\frac{[C_{2} H_{5}OH]}{[H_{2}O][C_{2} H_{4}]}$

According to the law of ideal gases,

PV = nRT

where P, V, n and T are the pressure, volume, moles and temperature of the gas in question while R is the gas constant (0.082057 atm L / mol K) .

We can use the ideal gas law to determine the molar concentrations ([x] = n / V) from the gas pressures of ethanol and water, assuming that all gases involved behave as ideal gases. In this way,

PV = nRT → P = (n/V) RT → P = [x] RT → [x] = P / RT

So,

$[C_{2} H_{5}OH] = \frac{200 atm}{0.082057 \frac{atm L}{mol K} x 600 K } = 4.06 \frac{mol}{L}$

$[H_{2}O] = \frac{400 atm}{0.082057 \frac{atm L}{mol K} x 600 K } = 8.12 \frac{mol}{L}$

So, the molar concentration of ethene (C₂H₄) will be,

$[C_{2} H_{4}] = \frac{[C_{2} H_{5}OH]}{[H_{2}O] x Kc} = \frac{4.06 \frac{mol}{L} }{8.12 \frac{mol}{L}x9.00 x 10^{3} \frac{L}{mol} } = 5.56 x 10^{-5}\frac{mol}{L}$

Then, according to the law of ideal gases,

$P_{C_{2} H_{4}} = [C_{2} H_{4}]RT = 5.56 x 10^{-5} \frac{mol}{L} x 0.082057 \frac{atm L}{mol K} x 600 K = 2.17x10^{-3} atm$

So, when the partial pressure of ethanol is 200 atm and the partial pressure of water is 400 atm, the partial pressure of ethene at 600 K is 2.17x10⁻³ atm.

7 0

3 years ago

A gas generation tube contains both the reactants involved in a chemical reaction and the gases that are produced.

Lady bird [3.3K]

The reaction will come to an end if all the reactants are used up. The reaction's limiting reactant is reactant B.

Limiting Reactant: The limiting reactant is the one that is consumed first and sets a limit on the quantity of product(s) that can be obtained.

This reactant is the one that restricts the production of products throughout the reaction. The reaction will come to an end if all of the reactants are used up.

surplus reactant

This is the limiting reactant that is present in excess and reacts with it all. Oxygen in the surroundings, as an illustration.

When all of the reactant B has been utilized, the reaction ends.

Learn more about limiting reactants here brainly.com/question/6751172

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5 0

2 years ago

Ethyl alcohol has a density of 0.80 g/mL. What is the volume of 44g of ethyl alcohol

Leya [2.2K]

Answer:

55mL

Explanation:

44g / 0.8g/mL = 55mL

4 0

3 years ago