Answer:
0.846 moles.
Explanation:
- This is a stichiometric problem.
- The balanced equation of complete combustion of butane is:
C₄H₁₀ + 6.5 O₂ → 4 CO₂ + 5 H₂O
- It is clear from the stichiometry of the balanced equation that complete combustion of 1.0 mole of butane needs 6.5 moles of O₂ to produce 4 moles of CO₂ and 5 moles of H₂O.
<u><em>Using cross multiplication:</em></u>
- 1.0 mole of C₄H₁₀ reacts with → 6.5 moles of O₂
- ??? moles of C₄H₁₀ are needed to react with → 5.5 moles of O₂
- The number of moles of C₄H₁₀ that are needed to react with 5.5 moles of O₂ = (1.0 x 5.5 moles of O₂) / (6.5 moles of O₂) = 0.846 moles.
To look for the value of the equilibrium constant for the cell where n=1, it is computed by:
Eo = RT / nF * ln(K)
(Eo * nF) /RT = ln(K)
(0.135 * 1mol* e- * 9.65E4C/mol*e) / (8.314J / molK * 298K) = ln(K)
10.52 = lnK
e^10.52 = e ^ lnK
K = e ^263/25
K = 37049.12 is the answer.
Answer:
182.3 g
Explanation:
number of mols of HCl = 5 mols
molecular weight of HCl = 36.46 g/mol
m = mass of HCl = number of mols x molecular weight
m = 5 mols * 36.46 g/mol
m = 182.3 g
Carbon dioxide, water;then energy source in sunlight and chlorophl maybe
