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Tpy6a [65]
4 years ago
9

If the freezing point of the solution had been incorrectly read 0.3 °C lower than the true freezing point, would the calculated

molar mass of the solute have been too high or too low? Explain.
Chemistry
1 answer:
Dovator [93]4 years ago
6 0

Answer : The molar mass of the solute would be low.

Explanation :

Formula used for depression in freezing point is:  

\Delta T_f=i\times K_f\times m\\\\T^o-T_s=i\times K_f\times\frac{w_b}{M_b}\times w_a}

where,

\Delta T_f = change in freezing point

\Delta T_s = freezing point of solution

\Delta T^o = freezing point of water

i = Van't Hoff factor

K_f = freezing point constant

m = molality

w_b = mass of solute

w_a = mass of solvent

M_b = molar mass of solute

From the formula we conclude that, when the freezing point of the solution read incorrectly that is freezing point of the solution is lower than the true freezing point then this means that change in freezing point would be high and the molar mass of the solute would be low.

Hence, the molar mass of the solute would be low.

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What is the total number of molecules in 11.2 liters of N2 gas at STP
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7 0
3 years ago
Which molecule will undergo only london dispersion forces when interacting with other molecules of the same kind?.
Neko [114]

Molecules undergo London dispersion forces:

C_{4}H_{10} is the molecule will undergo only London dispersion forces when interacting with other molecules of the same kind.

What are London dispersion forces?

  • A sort of force that interacts between atoms and molecules that is often electrically symmetric is referred to as a London dispersion force.
  • When viewed from the nucleus, their electron distribution is frequently symmetrical. This dispersion force, which is also known as a transient attractive force, is frequently observed when the locations of the electrons in two nearby atoms cause the atoms to temporarily form dipoles.
  • The bond is polar when there are significant variations between the elements' electronegativities; it is nonpolar when there are similarities. When the molecule's dipole moment is equal to O, it is nonpolar; when it differs from O, it is polar.
  • The force at these molecules is known as the London dispersion force. In nonpolar molecules, the forces are weak, and partial charges must be induced so that they can bond. In polar molecules, partial charges caused by polarity result in a stronger link known as a dipole-dipole. The dipole-dipole is significantly stronger and known as a hydrogen bond if it is connected to a large electronegative atom (F, O, or N). Ionic force is the name for the attraction force at ionic substances.
  • The intermolecular force in the letter an is the London dispersion force because the compound is nonpolar;

<u>Reason for incorrect options:</u>

b: the compound is ionic because Na is a metal and the other part is covalent,

c: two compounds are possible: one is nonpolar and exhibits London dispersion force; the other is polar and exhibits dipole-dipole force; and

d: both compounds exhibit hydrogen bonds (H bonded to O, and H bonded to F).

NOTE: Your question is incomplete, but most probably your full question was, which molecule will undergo only London dispersion forces when interacting with other molecules of the same kind? Which molecule will undergo only London dispersion forces when interacting with other molecules of the same kind?

A. C_{4}H_{10}

B. NaC_{2}H_{3}O_{2}

C. CH_{2}C_{12}

D. C_{2}H_{5}OH HF

Learn more about the London dispersion forces here,

brainly.com/question/22388709

#SPJ4

4 0
2 years ago
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