Answer:
269
Step-by-step explanation:
1) Substitute in the given values for each variable:
6(3)+23+(7)(33)-3
2) Simplify:
18+23+231-3
3) Simplify again:
269
Answer:
Fill up the .3 container and then pour it into the .5
fill up the .3 again and fill up the .5 ... if all is poured in the .5 will overflow over the top.
stop when the .5 is totally full... only .3 will fit... the liquid left in the .3 will be .1
Step-by-step explanation:
Answer:
There are about 1609 meters in 1 mile. ... in 1 mile
Answer:
first choice
Step-by-step explanation:
make 1/3 and 1/2 a common denominator, which is 6.
1x2
- = 2
-
3x 2 6
1 x 3
- = 3
-
2 x 3 6
now u have 2/6, and 3/6
u subtract 2/6 by 3/6 since ur finding a solution to an inequality. remember to do the opposite sign.
2/6-2/6 = 0 (u cancel that out)
3/6 - 2/6 = 1/6
now u have
q>1/6
since there's no 1/6 the first choice is the most accurate
Answer:
The absolute maximum is
and the absolute minimum value is 
Step-by-step explanation:
Differentiate of
both sides w.r.t.
,


Now take 



![\Rightarrow 1-2\sin ^2t =\sin t \quad \quad [\because \cos 2t = 1-2\sin ^2t]](https://tex.z-dn.net/?f=%5CRightarrow%201-2%5Csin%20%5E2t%20%3D%5Csin%20t%20%20%5Cquad%20%5Cquad%20%20%5B%5Cbecause%20%5Ccos%202t%20%3D%201-2%5Csin%20%5E2t%5D)






In the interval
, the answer to this problem is 
Now find the second derivative of
w.r.t.
,

![\Rightarrow \left[f''(t)\right]_{t=\frac {\pi}6}=-2\times \frac {\sqrt 3}2-4\times \frac{\sqrt 3}2=-3\sqrt 3](https://tex.z-dn.net/?f=%5CRightarrow%20%5Cleft%5Bf%27%27%28t%29%5Cright%5D_%7Bt%3D%5Cfrac%20%7B%5Cpi%7D6%7D%3D-2%5Ctimes%20%5Cfrac%20%7B%5Csqrt%203%7D2-4%5Ctimes%20%5Cfrac%7B%5Csqrt%203%7D2%3D-3%5Csqrt%203)
Thus,
is maximum at
and minimum at 
![\left[f(t)\right]_{t=\frac {\pi}6}=2\times \frac {\sqrt 3}2+\frac{\sqrt 3}2=\frac{3\sqrt 3}2\;\text{and}\;\left[f(t)\right]_{t=\frac{\pi}2}= 2\times 0+0=0](https://tex.z-dn.net/?f=%5Cleft%5Bf%28t%29%5Cright%5D_%7Bt%3D%5Cfrac%20%7B%5Cpi%7D6%7D%3D2%5Ctimes%20%5Cfrac%20%7B%5Csqrt%203%7D2%2B%5Cfrac%7B%5Csqrt%203%7D2%3D%5Cfrac%7B3%5Csqrt%203%7D2%5C%3B%5Ctext%7Band%7D%5C%3B%5Cleft%5Bf%28t%29%5Cright%5D_%7Bt%3D%5Cfrac%7B%5Cpi%7D2%7D%3D%202%5Ctimes%200%2B0%3D0)
Hence, the absolute maximum is
and the absolute minimum value is
.