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dmitriy555 [2]
3 years ago
7

r%7Bmagenta%7D%7B%20%5Cmaltese%7B%20%5Cunderline%7B%20%5Ccolor%7Bpink%7D%7B%20%5Ctextsf%7B%20%5Ctextbf%7BPRACTICAL%20GEOMETRY%7D%7D%7D%7D%7D%7D%7D%7D%7D%7D%7D" id="TexFormula1" title="{ \fcolorbox{cyan}{black}{ \huge{ \boxed{ \mathbb{ \color{magenta}{ \maltese{ \underline{ \color{pink}{ \textsf{ \textbf{PRACTICAL GEOMETRY}}}}}}}}}}}" alt="{ \fcolorbox{cyan}{black}{ \huge{ \boxed{ \mathbb{ \color{magenta}{ \maltese{ \underline{ \color{pink}{ \textsf{ \textbf{PRACTICAL GEOMETRY}}}}}}}}}}}" align="absmiddle" class="latex-formula">
construct a triangle ABC in which AB = 6cm media CD to AB = 4cm and altitude CE to AB = 3cm
\\  \\
Correct answer needed ​
Mathematics
1 answer:
mrs_skeptik [129]3 years ago
8 0

Answer:

➢ 1. Draw base AB of 6cm then construct 90° on A then take a compass and open it 4cm then from point A cut the arc on that 90° and name that point C. Join B to C triangle ABC will be the required triangle.

#CarryOnLearning...

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Evaluate 6j+23+kl−3, when j=3, k=7, and l=33.<br><br> Enter your answer in the box.
Umnica [9.8K]

Answer:

269

Step-by-step explanation:

1) Substitute in the given values for each variable:

6(3)+23+(7)(33)-3

2) Simplify:

18+23+231-3

3) Simplify again:

269

8 0
3 years ago
YOU HAVE A GARDEN HOSE AND A 0.5 LITER CONTAINER AND A 0.3 LITER CONTAINER. YOU NEED TO MEASURE OUT 0.1 LITER OF WATER. HOW DO Y
Nikitich [7]

Answer:

Fill up the .3 container and then pour it into the .5

fill up the .3 again and fill up the .5 ... if all is poured in the .5 will overflow over the top.

stop when the .5 is totally full... only .3 will fit... the liquid left in  the .3 will be .1

Step-by-step explanation:

7 0
3 years ago
Josh usually runs 9 laps around a track that is 400 meters long. There are about 1,609 meters in 1 mile. Which distance is close
Veseljchak [2.6K]

Answer:

There are about 1609 meters in 1 mile. ... in 1 mile

6 0
3 years ago
Choose the correct solution and graph inequality q + 1/3 &gt; 1/2​
kherson [118]

Answer:

first choice

Step-by-step explanation:

make 1/3 and 1/2 a common denominator, which is 6.

1x2

-      = 2

         -

3x 2   6

1 x 3  

-       =    3

             -

2 x 3      6

now u have 2/6, and 3/6

u subtract 2/6 by 3/6 since ur finding a solution to an inequality. remember to do the opposite sign.

2/6-2/6 = 0 (u cancel that out)

3/6 - 2/6 = 1/6

now u have

q>1/6

since there's no 1/6 the first choice is the most accurate

7 0
3 years ago
Find the absolute maximum and absolute minimum values of f on the given interval. f(t) = 2 cos(t) + sin(2t),[0, π/2].
castortr0y [4]

Answer:

The absolute maximum is \frac{3\sqrt 3}2 and the absolute minimum value is 0.

Step-by-step explanation:

Differentiate of f both sides w.r.t.  t,

f(t)=2 \cos t+\sin 2t

\Rightarrow f'(t)=-2\sin t+2\cos 2t

Now take f'(t)=0

\Rightarrow -2\sin t+2\cos 2t=0

\Rightarrow 2\cos 2t=2\sin t

\Rightarrow \cos 2t=\sin t

\Rightarrow 1-2\sin ^2t =\sin t  \quad \quad  [\because \cos 2t = 1-2\sin ^2t]

\Rightarrow 2\sin ^2t+\sin t-1=0

\Rightarrow 2\sin ^2t+2\sin t-\sin t-1=0

\Rightarrow 2\sin t(\sin t+1)-1(\sin t+1)=0

\Rightarrow (\sin t+1)(2\sin t-1)=0

\Rightarrow \sin t+1=0  \;\text{and}\; 2\sin t-1=0

\Rightarrow \sin t =-1  \;\text{and}\;   \sin t =\frac 12

In the interval 0\leq t\leq \frac {\pi}2, the answer to this problem is \frac {\pi}6

Now find the second derivative of f(t) w.r.t.   t,

f''(t)=-2\cos t-4\sin 2t

\Rightarrow \left[f''(t)\right]_{t=\frac {\pi}6}=-2\times \frac {\sqrt 3}2-4\times \frac{\sqrt 3}2=-3\sqrt 3

Thus, f(t) is maximum at t=\frac {\pi}6 and minimum at t=0

\left[f(t)\right]_{t=\frac {\pi}6}=2\times \frac {\sqrt 3}2+\frac{\sqrt 3}2=\frac{3\sqrt 3}2\;\text{and}\;\left[f(t)\right]_{t=\frac{\pi}2}= 2\times 0+0=0

Hence, the absolute maximum is \frac{3\sqrt 3}2 and the absolute minimum value is 0.

7 0
3 years ago
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