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nordsb [41]
2 years ago
15

Which of the following is NOT a benefit of fertilizer?

Biology
1 answer:
just olya [345]2 years ago
4 0

Answer:

Allows farmers to grow plants using very little soil

Explanation:

Fertilizer helps us to return the nutrients to the soil for new or current plants to grow. These nutrients were spent by the plants that were there or the soil was not that rich with nutrients, to begin with. It will not replace soil and growing plants without soil is called hydroponics. Fertilizer is very useful in agriculture currently and most likely will continue to be a good way to grow plants for a while.

You might be interested in
The four main types of macromolecules are organic. What does organic
inn [45]

Organic  means it is made only of carbon.

Explanation:

The all four types of macromolecule are organic means these all four type of macromolecule made up of carbon. These four macro molecules are carbohydrate, protein, nucleic acid and Proteins.  All are essential cell component perform a wide array of function.

Biological macromolecule is organic so they contain carbon. A part of carbon they contain nitrogen, hydrogen and additional minor element.   Enzymes and some hormone are example of protein.

4 0
3 years ago
Which of these is a consequence of over fertilization?
sveticcg [70]

Answer:

A. runoff

Explanation:

Runoff is a consequence of over fertilization.

This can be dangerous because it could cause the Mother and the babies to get disabilities or die.

5 0
3 years ago
In chickens, comb shape is determined by genes at two loci (R, r and P, p). A walnut comb is produced when at least one dominant
Ivenika [448]

Answer and Explanation:

<em><u>Available data</u></em>:

  • Comb shape is determined by genes at two loci (R, r and P, p).
  • The walnut comb genotype is R_P_.
  • The rose comb genotype is R_pp.
  • The pea comb genotype is rrP_.
  • The single genotype is rrpp.

a. <em>Walnut crossed with single produces 1 walnut, 1 rose, 1 pea, and 1 single offspring: </em>

Parental)             RrPp       x          rrpp

Gametes)   RP   Rp   rP   rp     rp   rp   rp   rp

Punnet Square)      RP       Rp     rP        rp

                     rp   <em>RrPp    Rrpp   rrPp   rrpp</em>

                     rp    RrPp    Rrpp   rrPp   rrpp

                     rp    RrPp    Rrpp   rrPp   rrpp

                     rp    RrPp    Rrpp   rrPp   rrpp

F1 phenotype: 25% walnut, 25% rose, 25% pea, and 25% single.

F1 genotype: 4/16 RrPp, 1/16 Rrpp, 4/16 rrPp, 4/16 rrpp.

b. <em>Rose crossed with pea produces 20 walnut offspring</em>.

Parental)              RRpp       x          rrPP

Gametes)   Rp   Rp   Rp   Rp     rP   rP   rP   rP

Punnet Square)      Rp       Rp     Rp        Rp

                     rP    RrPp    RrPp   RrPp   RrPp

                     rP    RrPp    RrPp   RrPp  RrPp

                    rP    RrPp    RrPp   RrPp   RrPp

                     rP    RrPp    RrPp   RrPp   RrPp

F1 phenotype: 100% walnut.

F1 genotype: 16/16 RrPp.

c. <em>Pea crossed with single produces 1 single offspring</em>.

This is not possible, because the pea genotype involves <u>at least</u> one dominant allele P. There are two possible crosses: <em>rrPp x rrpp</em>, which must produce half of the progeny pea and the other half single, or <em>rrPP x rrpp</em> which produce a whole pea progeny with no single offspring.  

Parental)              rrPp       x          rrpp

Gametes)   rP   rp   rP   rp     rp   rp   rp   rp

Punnet Square)     rP       rp       rP      rp

                     rp   <em>rrPp    rrpp   rrPp   rrpp</em>

                    rp    rrPp    rrpp   rrPp   rrpp

                     rp    rrPp    rrpp   rrPp   rrpp

                     rp    rrPp    rrpp   rrPp   rrpp

F1 phenotype: 50% pea, and 50% single.

F1 genotype: 8/16 rrPp, 8/16 rrpp.

d. <em>Rose crossed with pea produces 2 walnut, 1 single, and 1 pea offspring</em>.

This is not possible, because having one of the parents with a rose phenotype  involves <u>at least one R allele</u>, which means that <u>there must be rose phenotype</u> in the progeny.

Parental)             Rrpp       x          rrPp

Gametes)   Rp   Rp   rp   rp     rP   rP   rp   rp

Punnet Square)     Rp       Rp       rp      rp

                     rP  <em> RrPp </em>   RrPp  <em> rrPp</em>   rrPp

                     rP   RrPp    RrPp   rrPp   rrPp

                     rp    <em>Rrpp</em>    Rrpp   <em>rrpp </em>  rrpp

                     rp   Rrpp    Rrpp   rrpp   rrpp

F1 phenotype: 25% walnut, 25% rose, 25% pea, and 25% single.

F1 genotype: 4/16 RrPp, 1/16 Rrpp, 4/16 rrPp, 4/16 rrpp.

e. <em>Rose crossed with single produces 31 rose offspring</em>.

Parental)              RRpp       x          rrpp

Gametes)   Rp   Rp   Rp   Rp     rp   rp   rp   rp

Punnet Square)     Rp       Rp       Rp      Rp

                     rp    Rrpp    Rrpp   Rrpp   Rrpp

                     rp    Rrpp    Rrpp   Rrpp   Rrpp

                     rp    Rrpp    Rrpp   Rrpp   Rrpp

                     rp    Rrpp    Rrpp   Rrpp   Rrpp

F1 phenotype: 100% rose (31 individuals equal 100% of the progeny).

F1 genotype: 16/16 Rrpp.

f. <em>Rose crossed with single produces 10 rose and 11 single offspring.</em>

Parental)              Rrpp       x          rrpp

Gametes)   Rp   Rp   rp   rp     rP   rP   rp   rp

Punnet Square)      Rp       Rp       rp      rp

                     rp    Rrpp    Rrpp   rrpp   rrpp

                     rp    Rrpp    Rrpp   rrpp   rrpp

                     rp    Rrpp    Rrpp   rrpp   rrpp

                     rp    Rrpp    Rrpp   rrpp   rrpp

F1 phenotype: 50% rose, 50% single.

F1 genotype: 8/16 Rrpp, 8/16 rrpp.

3 0
3 years ago
The Sun appears to move from ______________________ to _______________________________across the sky
I am Lyosha [343]

Answer:

East to West

Explanation:

6 0
3 years ago
Identical population-splitting events occurred simultaneously on two neighboring islands, Islands B and C, which are each initia
sweet-ann [11.9K]

Answer:

This is due to the event of Speciation that happened for the rodents in Island B but not for the rodents in Island C.

Explanation:

  • Due to splitting of the population,
  • The sub-population of rodents formed in Island B are B1 and B2.
  • The sub-population of rodents formed in Island C are C1 and C2.
  • In case of Island B, each of the B1 and B2 sub-populations that got split from each other developed certain mutations that were necessary for them to adapt to the particular diverse environment each of them were exposed to, through the period of 50,000 years. These mutations were so varied that reproductive isolation was generated between them that resulted in each of them to develop into different species.Hence, speciation happens here and B1 and B2 are incapable of inter-breeding.
  • In case of Island C, each of the C1 and C2 sub-populations that got split might have got exposed to similar environmental change or no environmental change or the environmental change might have been too small to cause drastic change in each of the sub-populations. As a result of this the two sub-populations might have acquired certain mutations to adapt to the environment each of them were exposed to, through a period of 100,000 years. These mutations might not have been too variable or contrasting to cause reproductive isolation between C1 and C2. Hence, no new speciation happens here and C1 and C2 are capable of inter-breeding.

4 0
2 years ago
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