Answer:
A= 20%
G= 30%
T= 20%
C= 30%
Explanation:
Recall that the sum of all nitrogenous bases in the DNA nucleotide is equal to 100%. And specific base pairings of Adenine to Thymine (A=T), and Cytosine to Guanine (C=G) must be equal.
So, the percentage of Adenine equal thymine, and that of cytosine equals guanine.
Now, A + T + C + G = 100%
So, if Adenine makes up 20% of the DNA nucleotides, Thymine is also 20%.
Then, 20% + 20% + C + G = 100%
40% + C + G = 100%
C + G = 100% - 40% = 60%
So, divide 60% by 2 to obtain the individual percentage of cytosine and guanine. Each will take 30%
Finally, A= 20%; G= 30%; T= 20%; C= 30%
Answer:
D. glucose.
Explanation:
I don't have any info on it so, hope this helps.
Cells that are mainly (alive) and that have more then 1 cell
PROKARYOTES ARE SINGLE CELLED ORGANISMS
Answer:
- Only fMet-tRNA(fMet) can bind first to the P site in the ribosome. ( A )
- There are more than one tRNA with the 5' CAU 3' anticodon. ( B )
- The N-formyl group attached to methionine prevents fMet from entering interior positions in a polypeptide. ( D )
Explanation:
The statements that explains how N--formyl methionine (fMet) is only associated with the 5' AUG initiation codon and not with internal AUG codons, given that methionine in both cases in encoded by an AUG in the mRNA are :
Only fMet-tRNA(fMet) can bind first to the P site in the ribosome. ( A )
There are more than one tRNA with the 5' CAU 3' anticodon. ( B )
The N-formyl group attached to methionine prevents fMet from entering interior positions in a polypeptide. ( D )
While statement C is wrong.
In swamps and bogs, there are less nutrients for the plants to obtain, therefore depending on the use of trapping insects to get their nutrients they need.
