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kap26 [50]
1 year ago
5

You receive a prescription for amoxicillin 75 mg qid for ten days. how many ml's do you need to fill this prescription to last t

he full ten days using amoxicillin 125 mg/5 cc?
Chemistry
1 answer:
pochemuha1 year ago
5 0

According to the question:

Given,

= 250mg 75mg 375mg

= 5Cc X 250 X

= X = 1.5ml

= 1.5ml/dose X 4 doses/daily X 10 days = 60 ml

<h3>What do you know about amoxicillin?</h3>

Numerous bacterial infections can be treated with amoxicillin. This drug is an antibiotic similar to penicillin. It acts by preventing bacterial development. Only bacterial illnesses are treated by this antibiotic. For viral infections, it is ineffective (such as common cold, flu). Any antibiotic that is overused may stop working to treat subsequent illnesses. Along with other drugs, amoxicillin is also used to treat and prevent the recurrence of stomach / intestinal ulcers brought on by the bacteria H. pylori. Take this medication by mouth every 8 to 12 hours, generally with or without food, as prescribed by your doctor. Your medical condition and treatment response will determine the dosage.

To know more about  Amoxicillin, visit:

<u>brainly.com/question/14445732</u>

#SPJ4.

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Which of the following represents an endothermic reaction?
Softa [21]

Answer:

<h2><em><u>A</u></em><em><u>N</u></em><em><u>S</u></em><em><u>W</u></em><em><u>E</u></em><em><u>R</u></em></h2>

The second one would be one of the application of an endothermic reaction as because endothermic reaction always have the heat in the process to mix the reactants and form the products as here in a burning wood when the wood is supplied with heat then it change into products as ashes and smoke fumes So here due to the heat is involved to form the products thats the reaction is endothermic reaction.

Hope it helps

8 0
3 years ago
Separate this redox reaction into its balanced component half-reactions. What is the oxidation and reduction half reactions
erma4kov [3.2K]
<span>Separate this redox reaction into its component half-reactions. 
Cl2 + 2Na ----> 2NaCl 

reduction: Cl2 + 2 e- ----> 2Cl-1 
oxidation: 2Na ----> 2Na+ & 2 e- 


2) Write a balanced overall reaction from these unbalanced half-reactions: 

oxidation: Sn ----> Sn^2+ & 2 e- 
reduction: 2Ag^+ & 2e- ----> 2Ag 

giving us 
2Ag^+ & Sn ----> Sn^2+ & 2Ag </span>Steve O <span>· 5 years ago </span><span>
</span>
3 0
3 years ago
Read 2 more answers
Which organism on the food chain is a carnivore? fungus grass grasshopper spider
Lady_Fox [76]

Answer:

I think it would it spider

Explanation:

Spider catch there meals in there web then suck the blood out after it wraps them up in webing

5 0
3 years ago
Milk of magnesia, a suspension of mg(oh)2 in water, reacts with stomach acid (hcl) in a neutralization reaction. mg(oh)2(s) + 2
defon
Balanced equation for the above reaction is as follows;
Mg(OH)₂ + 2HCl ---> MgCl₂ + 2H₂O
stoichiometry of Mg(OH)₂ to MgCl₂ is 1:1
mass of Mg(OH)₂ reacted - 1.82 g
number of moles of Mg(OH)₂  - 1.82 g/ 58.3 g/mol = 0.0312 mol
number of Mg(OH)₂  moles reacted - number of MgCl₂ moles formed 
number of MgCl₂ moles formed - 0.0312 mol
mass of MgCl₂ formed - 0.0312 mol x 95.2 g/mol = 2.97 g
mass of MgCl₂ formed - 2.97 g

5 0
3 years ago
During a titration the following data were collected. A 50.0 mL portion of an HCl solution was titrated with 0.500 M NaOH; 200.
Travka [436]

<u>Answer:</u> The mass of HCl present in 500 mL of acid solution is 36.5 grams

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=1\\M_1=?M\\V_1=50.00mL\\n_2=1\\M_2=0.500M\\V_2=200.mL

Putting values in above equation, we get:

1\times M_1\times 50.00=1\times 0.500\times 200\\\\M_1=\frac{1\times 0.500\times 200}{1\times 50.00}=2M

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

Molar mass of HCl = 36.5 g/mol

Molarity of solution = 2 M

Volume of solution = 500 mL

Putting values in above equation, we get:

2mol/L=\frac{\text{Mass of solute}\times 1000}{36.5g/mol\times 500}\\\\\text{Mass of solute}=\frac{2\times 36.5\times 500}{1000}=36.5g

Hence, the mass of HCl present in 500 mL of acid solution is 36.5 grams

4 0
3 years ago
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