1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
dedylja [7]
2 years ago
14

in a given homologous series of hydrocarbons, the boiling point generally increases as the size of the molecules increases. the

best explanation for this statement is that in larger organic molecules
Chemistry
1 answer:
vitfil [10]2 years ago
5 0

The boiling point of hydrocarbons generally increases as the size of the molecules increases because more bonds are needs to be broken in larger organic molecules.

<h3>What are hydrocarbons?</h3>

Hydrocarbons are organic compounds which here composed of hydrogen and carbon alone.

Hydrocarbons are grouped into families or homologous series based on a reactive group known as the gincyiial group

The homologous series include

  • alkanes
  • alkenes
  • alkynes

The boiling point generally increases as the size of the molecules increases because more bonds are needs to be broken in larger organic molecules.

Learn more about hydrocarbons at: brainly.com/question/3551546

#SPJ1

You might be interested in
Please Help, will give 30 points! The following data was collected when a reaction was performed experimentally in the laborator
Sedaia [141]

Answer:

9 moles of NaNO3.

Explanation:

The balanced equation for the reaction is given below:

Al(NO3)3 + 3NaCl —> 3NaNO3 + AlCl3

Next, we shall determine the number of mole of Al(NO3)3 and NaCl that reacted and the number of mole of NaNO3 produced from the balanced equation.

From the balanced equation above,

1 mole of Al(NO3)3 reacted with 3 moles of NaCl to produce 3 moles of NaNO3.

Next, we shall determine the limiting reactant.

The limiting reactant can be obtained as follow:

From the balanced equation above,

1 mole of Al(NO3)3 reacted with 3 moles of NaCl.

Therefore, 4 moles of Al(NO3)3 will react with = (4 x 3)/1 = 12 moles of NaCl.

From the calculations made above, we can see that it will take a higher amount i.e 12 moles than what was given i.e 9 moles of NaCl to react completely with 4 moles of Al(NO3)3.

Therefore, NaCl is the limiting reactant and Al(NO3)3 is the excess reactant.

Finally, we shall determine the maximum amount of NaNO3 produced from the reaction.

In this case, the limiting reactant will be used as it will produce the maximum amount of NaNO3 since all of it is consumed by the reaction.

The limit reactant is NaCl and the maximum amount of NaNO3 produced can be obtained as follow:

From the balanced equation above,

3 moles of NaCl reacted to produce 3 moles of NaNO3.

Therefore, 9 moles of NaCl will also react to produce 9 moles of NaNO3.

From the calculations made above, the maximum amount of NaNO3 produced is 9 moles

6 0
3 years ago
Plz help ASAP it’s dude soon
Alex_Xolod [135]

Answer:

a

Explanation:

6 0
2 years ago
Compare the rates of effusion for carbon monoxide and carbon dioxide gases
Airida [17]
According to Grahams law the rate of effusion of a gas is inversely proportional to the square root of it's molecular weight. The rate of diffusion is the measure of rate at which two gases mix. From this law we can say that for the two gases carbon monoxide and carbon dioxide, the rate of effusion of carbon monoxide is greater than that of carbon dioxide, this is because carbon monoxide is lighter (28 g) compared to carbon dioxide (44 g). 
7 0
2 years ago
Tarnish on copper is the compound CuO. A tarnished copper plate is placed in an aluminum pan of boiling water. When enough salt
oksian1 [2.3K]

Answer:

The standard cell potential is 2.00 V

Explanation:

<u>Step 1:</u> Data given

Cu is cathode because of higher EP

Al3++3e−→Al       E∘=−1.66 V     anode

Cu2++2e−→Cu    E∘=0.340 V    cathode

<u>Step 2:</u> Balance both equations

2*(Al → Al3+-3e−)       E∘=1.66 V    

3*(Cu2++2e−→Cu)    E∘=0.340 V

<u>Step 3:</u> The netto equation

2 Al + 3Cu2+ +6e- → 2Al3+ + 3Cu -6e-

2 Al + 3Cu2+  → 2Al3+ + 3Cu

<u>Step 4:</u> Calculate the standard cell potential

E∘cell = E∘cathode - E∘anode

E∘cell = E∘ Cu2+/Cu - E∘ Al3+/Al

E∘cell =0.340 V - (-1.66) = 2.00 V

The standard cell potential is 2.00 V

4 0
2 years ago
What equation represents the pressure of a gas under ideal conditions?
Leno4ka [110]
P=nRTV
hope this help<span />
8 0
3 years ago
Read 2 more answers
Other questions:
  • An unknown substance has been shown to have metallic bonds.
    6·2 answers
  • A compound contains 47.08% carbon, 6.59% hydrogen and 46.33% chlorine by mass. what is the empirical formula for the compound.
    11·1 answer
  • What are seeds made out of?
    12·1 answer
  • How many moles of NO can be formed when 2.86 mol of N2 reacts?
    11·1 answer
  • How many grams of co are in 125 ml of a 0.25 m solution? 0.87 g 1.1 g 14 g 880 g?
    15·1 answer
  • Hillsdale and Cordera are the same distance from the equator, and both are near the ocean. Is Cordera warmer, colder, or the sam
    12·2 answers
  • The 3 types of heat transfer are convection, radiation, connected.<br> A. True<br> B. False
    13·1 answer
  • How do you balance the following equation only using coefficients?
    15·1 answer
  • How to calculate the sum of the ratio of the ions
    10·1 answer
  • Hydrogen bromide breaks down into diatomic hydrogen and bromine in the reaction shown.
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!