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dedylja [7]
2 years ago
14

in a given homologous series of hydrocarbons, the boiling point generally increases as the size of the molecules increases. the

best explanation for this statement is that in larger organic molecules
Chemistry
1 answer:
vitfil [10]2 years ago
5 0

The boiling point of hydrocarbons generally increases as the size of the molecules increases because more bonds are needs to be broken in larger organic molecules.

<h3>What are hydrocarbons?</h3>

Hydrocarbons are organic compounds which here composed of hydrogen and carbon alone.

Hydrocarbons are grouped into families or homologous series based on a reactive group known as the gincyiial group

The homologous series include

  • alkanes
  • alkenes
  • alkynes

The boiling point generally increases as the size of the molecules increases because more bonds are needs to be broken in larger organic molecules.

Learn more about hydrocarbons at: brainly.com/question/3551546

#SPJ1

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A sample of gas contains 0.1100 mol of HBr(g) and 5.00x10^-2 mol of Cl2(g) and occupies a volume of 5.85 L. The following reacti
Vesna [10]

The volume of the sample after the reaction : V₂=5.484 L

<h3>Further explanation</h3>

Given

Reaction

2HBr(g) + Cl2(g) => 2HCl (g)+Br2(g)

0.1100 mol of HBr(g)

5x10⁻² mol of Cl2(g)

Required

The volume of the sample after reaction

Solution

Find limiting reactant :

0.11/2 : 0.05/1 = 0.055 : 0.05

Limiting reactant : Cl₂

mol Products based on mol Cl₂

mol products = mol HCl + mol Br₂

mol products = 2/1x0.05 + 1/1x0.05

mol products = 3 x 0.05 = 0.15

mol reactants = 0.11 + 0.05 = 0.16

<em>From Avogadro's law, </em>

In the same T, P, and V, the gas contains the same number of molecules  

So the ratio of gas volume will be equal to the ratio of gas moles  

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1 = reactants, 2 = products

Input the value :

5.85/0.16=V₂/0.15

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