Answer:
We normally separate unreacted hydrogen from ammonia (product) in Haber process. The reaction mixture contains some ammonia, plus a lot of unreacted hydrogen and nitrogen. The mixture is cooled and compressed, causing the ammonia gas to condense into a liquid.
C₀=2 mol/l
c₁=0.400 mol/l
v₁=100.0 ml = 0.1 l
c₁v₁=c₀v₀
v₀=c₁v₁/c₀
v(H₂O)=v₁-v₀
v₀=0.1*0.400/2=0.02 l = 20 ml
v(H₂O)=100 - 20 = 80 ml
It is necessary to mix 20 ml of the feed solution and 80 ml of water.
I would say : D) Newton's 3rd law of motion.
-Hope this helps.
<u>Answer:</u>
3.67 moles
<u>Step-by-step explanation:</u>
We need to find out the number of 
moles present in 350 grams of a compound.
Molar mass of 
= 24.305
Molar mass of 
= 35.453
So, one mole of = 24.305 + (35.453 * 2) = 95.211g
1 Mole in 1 molecule of = 
Therefore, number of moles in 350 grams of compound = 0.0105 * 350
= 3.67 moles
