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Anna11 [10]
3 years ago
15

If you could help I would really appreciate it, but if not that’s fine. Thank you.

Mathematics
1 answer:
tigry1 [53]3 years ago
5 0
Since 6 is greater than 5 you input it into the last equation!

2•(6^2) -7
2•(36) -7
72 -7
65

The answer is 65!
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What is the trip fuel cost for a 600 mile trip if the average cost per mile of a car is
larisa [96]

Answer:

C. $114

Step-by-step explanation:

Take the cost per mile times the miles traveled.

0.19 x 600 Multiply

114

4 0
3 years ago
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A jump rope is 9 ft long . how long is the jump rope in yards
pav-90 [236]
The rope would be 3 yards long because every 3 feet is equal to 1 yard
7 0
3 years ago
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Solving Rational equations. LCD method. Show work. Image attached.
Dmitry [639]

Answer:

b=1

Step-by-step explanation:

The given rational equation is

\frac{2b-5}{b-2} -2=\frac{3}{b+2}

The Least Common Denominator is (b+2)(b-2).

Multiply each term in the equation by the LCD.

(b+2)(b-2)\times \frac{2b-5}{b-2} -(b+2)(b-2)\times2=(b+2)(b-2)\times\frac{3}{b+2}

Simplify;

(b+2)\times \frac{2b-5}{1} -2(b+2)(b-2)=(b-2)\times\frac{3}{1}

(b+2)(2b-5) -2(b+2)(b-2)=3(b-2)

Expand and group similar terms

2b^2-5b+4b-10 -2(b^2-4)=3b-6

2b^2-5b+4b-10 -2b^2+8=3b-6

-b-2=3b-6

3b+b=-2+6

4b=4

b=1

3 0
3 years ago
Assume a warehouse operates 24 hours a day. Truck arrivals follow Poisson distribution with a mean rate of 36 per day and servic
kirill [66]

The expected waiting time in system for typical truck is 2 hours.

Step-by-step explanation:

Data Given are as follows.

Truck arrival rate is given by,   α  = 36 / day

Truck operation departure rate is given,   β= 48 / day

A constructed queuing model is such that so that queue lengths and waiting time can be predicted.

In queuing theory, we have to achieve economic balance between number of customers arriving into system and that of leaving the system whether referring to people or things, in correlating such variables as how customers arrive, how service meets their requirements, average service time and extent of variations, and idle time.

This problem is solved by using concept of Single Channel Arrival with exponential service infinite populate model.

Waiting time in system is given by,

w_{s} = \frac{1}{\alpha - \beta  }

        where w_s is waiting time in system

                   \alpha is arrival rate described Poission distribution

                   \beta is service rate described by Exponential distribution

w_{s} = \frac{1}{\alpha - \beta  }

w_{s} = \frac{1}{48 - 36 }

w_{s} = \frac{1}{12 } day

w_{s} = \frac{1}{12 }  \times 24  hour        ...it is due to 1 day = 24 hours

w_{s} = 2 hours

Therefore, time required for waiting in system is 2 hours.

           

                   

5 0
3 years ago
A jar contains 8 red marbles, 10 blue marbles, and 2 yellow marbles. One marble is chosen at random. The color is recorded in th
NeX [460]

Answer:

blue is more likely to be chosen because there are more of them than the other colors

Step-by-step explanation:

6 0
3 years ago
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