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tino4ka555 [31]
3 years ago
10

Which of the following would be most useful in trying to obtain procedural information to replicate an experiment previously pub

lished?
Chemistry
1 answer:
Jet001 [13]3 years ago
7 0

Answer: Peer-reviewed journal article is the most useful because the information in them had been carefully scrutinized and aproved by people who are experts in that particular field.

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key A 0.150 M sodium chloride solution is referred to as a physiological saline solution because it has the same concentration o
lorasvet [3.4K]

Answer:

2.41065 grams

Explanation:

Here we have to apply molarity, particularly in reference to the equation molarity = moles of solute / volume. I would like to rewrite this formula, but with respect to the units - grams = moles / Liters,

We can use molarity to determine the number of moles. After doing so, we can determine the mass of the solute with respect to the formula moles = mass / molar mass. The molar mass of NaCl is 58.44 grams.

_______________________________________________________

275 mL = 0.275 L,

Number of Moles of NaCl = 0.150 * 0.275 = 0.04125 moles,

Mass = 0.04125 * 58.44 = 2.41065 grams,

Solution - Mass of NaCl = 2.41065 grams

<u><em>Hope that helps!</em></u>

5 0
2 years ago
Read 2 more answers
PLEASE HELP!!
sp2606 [1]
Inbox me for the answer

6 0
2 years ago
In order to calculate the number of neutrons you must subtract the what from the what?​
Katyanochek1 [597]

Answer:

You take the atomic, or proton number of the element, and you subtract it from the element's mass number.

6 0
3 years ago
Read 2 more answers
The [OH-] of a solution is 7.89 10^-12 M. What is the pH of the solution? it acidic or basic? *
kompoz [17]

Answer: pH = 2,897 , basic[H+][OH-] = 10^{-14} ==> [H+] = \frac{10^{-14}}{7,89*10^{-12} } =\frac{1}{789} \\pH= -lg([H+]) = 2,897 \\pH basic

Explanation:

6 0
3 years ago
Which element is oxidized in the reaction below? fe(co)5 (l) + 2hi (g) fe(co)4i2 (s) + co (g) + h2 (g)?
DanielleElmas [232]
Oxidation state of I is (-1) and for CO it is zero. Let's assume that the oxidation state of Fe in Fe(CO)₄I₂<span> (s) is x. For whole compound, the charge is zero.

Sum of oxidation numbers in all elements = Charge of the compound.

Here we have 1Fe , 4CO and 2I
hence we can find the oxidation state as;
 x + 4*0 + 2*(-1) = 0
 x + 0 - 2            = 0
                   x     = +2
Hence the oxidation state of Fe in product </span>Fe(CO)₄I₂ (s) is +2.

Same as we can find the oxidation state (y) of Fe in Fe(CO)₅(s).
y + 5*0 = 0
   y        = 0

Since oxidation state of Fe increased from 0 to +2, the oxidized element is Fe in the given reaction.
5 0
2 years ago
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