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3 years ago

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Describe a main goal of secondary treatment in a modern sewage treatment plant.

2 answers:

Vikki [24]3 years ago

6 0

Answer:

Explanation:

The main goal of secondary treatment is the further treatment of the liquid waste from primary treatment to remove the residual organics and suspended solids. Most times, secondary treatment follows primary treatment and involves the removal of biodegradable dissolved and colloidal organic matter using aerobic biological treatment processes. Aerobic biological treatment as the name implies, it is performed in the presence of oxygen by aerobic microorganisms (principally bacteria) that metabolize the organic matter in the wastewater, thereby producing more microorganisms and inorganic end-products majorly CO2, NH3, and H2O.

prohojiy [21]3 years ago

4 0

Answer:

A wastewater treatment plant serves to evacuate solids, reducing organic matter and present pollutants, thus restoring oxygen. Bacteria and other microorganisms are used to reduce organic matter and pollutants, so that they consume the organic matter present in the waste water.

The primary purpose of secondary treatment is to improve the process so that at least 90% of all contaminants are evacuated. The equipment used for this purpose is an aeration tank, which supplies large amounts of air to a mixture of wastewater, bacteria and microorganisms. The oxygen found in the injected air increases the growth of microorganisms, so that they consume the organic matter found in the waste water.

Explanation:

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Determine the mole fractions and partial pressures of CO2, CH4, and He in a sample of gas that contains 1.20 moles of CO2, 1.79

BARSIC [14]

Answer : The mole fraction and partial pressure of $CH_4,CO_2$ and $He$ gases are, 0.267, 0.179, 0.554 and 1.54, 1.03 and 3.20 atm respectively.

Explanation : Given,

Moles of $CH_4$ = 1.79 mole

Moles of $CO_2$ = 1.20 mole

Moles of $He$ = 3.71 mole

Now we have to calculate the mole fraction of $CH_4,CO_2$ and $He$ gases.

$\text{Mole fraction of }CH_4=\frac{\text{Moles of }CH_4}{\text{Moles of }CH_4+\text{Moles of }CO_2+\text{Moles of }He}$

$\text{Mole fraction of }CH_4=\frac{1.79}{1.79+1.20+3.71}=0.267$

and,

$\text{Mole fraction of }CO_2=\frac{\text{Moles of }CO_2}{\text{Moles of }CH_4+\text{Moles of }CO_2+\text{Moles of }He}$

$\text{Mole fraction of }CO_2=\frac{1.20}{1.79+1.20+3.71}=0.179$

and,

$\text{Mole fraction of }He=\frac{\text{Moles of }He}{\text{Moles of }CH_4+\text{Moles of }CO_2+\text{Moles of }He}$

$\text{Mole fraction of }He=\frac{3.71}{1.79+1.20+3.71}=0.554$

Thus, the mole fraction of $CH_4,CO_2$ and $He$ gases are, 0.267, 0.179 and 0.554 respectively.

Now we have to calculate the partial pressure of $CH_4,CO_2$ and $He$ gases.

According to the Raoult's law,

$p_i=X_i\times p_T$

where,

$p_i$ = partial pressure of gas

$p_T$ = total pressure of gas = 5.78 atm

$X_i$ = mole fraction of gas

$p_{CH_4}=X_{CH_4}\times p_T$

$p_{CH_4}=0.267\times 5.78atm=1.54atm$

and,

$p_{CO_2}=X_{CO_2}\times p_T$

$p_{CO_2}=0.179\times 5.78atm=1.03atm$

and,

$p_{He}=X_{He}\times p_T$

$p_{He}=0.554\times 5.78atm=3.20atm$

Thus, the partial pressure of $CH_4,CO_2$ and $He$ gases are, 1.54, 1.03 and 3.20 atm respectively.

4 0

3 years ago

What happens when chemical bonds break and new bonds form

zheka24 [161]

Answer:

Chemical reactions make and break the chemical bonds between molecules, resulting in new materials as the products of the chemical reaction.

Explanation:

Breaking chemical bonds absorbs energy, while making new bonds releases energy, with the overall chemical reaction being endothermic or exothermic.

5 0

3 years ago

Help Please!!!!!!!!!!!!!!!!!!!!!!

RUDIKE [14]

Answer:

B

Explanation:

7 0

3 years ago

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Which of the following is the correct representation of Gibbs’ Free Energy equation?

777dan777 [17]

The correct answer is: [A]: " <span>∆G=∆H-T∆S ".
______________________________________________</span>

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3 years ago

How does acid precipitation change rock over time?

Veronika [31]

It weathers it down until it is nothing but sediment in a river , lake or ocean

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3 years ago