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Assoli18 [71]
3 years ago
8

Describe a main goal of secondary treatment in a modern sewage treatment plant.

Chemistry
2 answers:
Vikki [24]3 years ago
6 0

Answer:

Explanation:

The main goal of secondary treatment is the further treatment of the liquid waste from primary treatment to remove the residual organics and suspended solids. Most times, secondary treatment follows primary treatment and involves the removal of biodegradable dissolved and colloidal organic matter using aerobic biological treatment processes. Aerobic biological treatment as the name implies, it is performed in the presence of oxygen by aerobic microorganisms (principally bacteria) that metabolize the organic matter in the wastewater, thereby producing more microorganisms and inorganic end-products majorly CO2, NH3, and H2O.

prohojiy [21]3 years ago
4 0

Answer:

A wastewater treatment plant serves to evacuate solids, reducing organic matter and present pollutants, thus restoring oxygen. Bacteria and other microorganisms are used to reduce organic matter and pollutants, so that they consume the organic matter present in the waste water.

The primary purpose of secondary treatment is to improve the process so that at least 90% of all contaminants are evacuated. The equipment used for this purpose is an aeration tank, which supplies large amounts of air to a mixture of wastewater, bacteria and microorganisms. The oxygen found in the injected air increases the growth of microorganisms, so that they consume the organic matter found in the waste water.

Explanation:

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Gas burning in an engine is an example of a
pav-90 [236]
The answer is the first option. Gas burning in an engine is an example of a chemical change. Chemical change is a change where the substance changes in identity or form new substances after undergoing a process. In this case, the gas reacts with oxygen forming combustion products, commonly carbon dioxide and water.
8 0
3 years ago
0.102 g of an unknown(non electrolyte) compound is dissolved in enough water to make 100. mL of a solution and has an osmotic pr
Leni [432]

Answer:

680 g/m is the molar mass for the unknown, non electrolyte, compound.

Explanation:

Let's apply the formula for osmotic pressure

π = Molarity . R . T

T = T° absolute (in K)

R = Universal constant gases

π = Pressure

Molarity = mol/L

As units of R are  L.atm/mol.K, we have to convert the mmHg to atm

760 mmHg  is 1 atm

28.1 mmHg is (28.1  .1)/760 = 0.0369 atm

0.0369 atm = M . 0.082 L.atm/mol.K . 293K

(0.0369 atm / 0.082 mol.K/L.atm . 293K) = M

0.0015 mol/L = Molarity

This data means the mol of solute in 1L, but we have 100mL so

Molarity . volume = mol

0.0015 mol/L . 0.1L = 1.5x10⁻⁴ mole

The molar mass will be: 0.102g / 1.5x10⁻⁴ m = 680 g/m

4 0
3 years ago
Help pls pls pls I really need this answer
blagie [28]

Answer:

I never did this but i think its d 37.5٪ lmk if i got it right pls and srry if i didnt

5 0
3 years ago
If your lawn is 21.0 ft wide and 20.0 ft long, and each square foot of lawn accumulates 1350 new snow flakes every minute. How m
GaryK [48]
<span>First we can calculate the area of the rectangular lawn using the formula:
Area = Width x Length = 21 ft x 20 ft = 420 square feet
       
And the total number of snow flakes per minute on the entire lawn is:
   
(1350 snowflakes per minute per square foot) x (420 square feet) = 567,000 snowflakes per minute
       
In one hour (or 60 minutes) we get a total of:
   
(567,000 snowflakes per minute) x (60 minutes / 1 hour) = 34,020,000 snowflakes
       
The total mass of which would be:
   
34,020,000 snowflakes x 1.60 mg = 54,432,000 mg = 54.432 kg (as 1 kg = 1,000,000 mg).
       
So 54.432 kg of snow accumulates every hour on the lawn.</span>
7 0
3 years ago
Somebody answer please a picture is attached!??
DanielleElmas [232]
9.2 that is the answer
7 0
3 years ago
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