33% of the total compound is SO2
An applied force is the force exerted on an object with the intent to move it. Frictional force is the force that opposes motion. Static friction acts on objects at rest and prevents them from moving. Kinetic friction acts on objects in motion and works in a direction opposite to the motion. Air resistance is a kind of friction exerted by air on moving objects.
Normal force is exerted on an object by the surface it is resting on to support its weight. Spring force is exerted by either a compressed or stretched spring. Tension force is the force acting on a rope or a string that is pulled tight by a load attached to it. Gravitational force is the attractive force that acts between two objects. It is directly proportional to the mass of the object, which means that heavier objects have a more pronounced gravitational force. Magnetic force is the force between two magnetic poles, which may be attractive for unlike poles or repulsive for like poles. Electrical force is the force between two electrical charges, which also may be attractive for unlike charges and repulsive for like charges.
Answer:
1254 J
Explanation:
Mass, m = 10.0g
Initial Temperature = 20°C
Final Temperature = 50°C
Energy = ?
Specific heat capacity, c = 4.18 J/g·°C
The relationship between these quantities is given by the equation;
H = mcΔT
ΔT = Final Temperature - Initial Temperature = 50 - 20 = 30 °C
H = 10 * 4.18 * 30
H = 1254 J
Answer:
941 K (668°C)
Explanation:
We have the following data:
Initial pressure : P1 = 1.45 atm
Initial temperature: T1 = 52°C + 273 = 325 K
Final pressure: P2 = 4.2 atm
Final temperature: T2 = ?
The relation between pressure and temperature for a gas at constant volume is given by Gay-Lussac's law:
P1/T1 = P2/T2
That means that the pressure is directly proportional to the absolute temperature (in K). So, we calculate T2 from the equation:
T2 = P2 x T1/P1 = 4.2 atm x (325 K/1.45 atm) = 941 K
Therefore, the final temperature would be 941 K (668°C). This is consistent with the law, that states that if the pressure increase, the temperature will be increased.
<span>c. q = 0.75 g x 0.897 j/g•°c x 22°c</span>