Answer:
IO₂
Explanation:
We have been given the mass percentages of the elements that makes up the compound:
Mass percentage given are:
Iodine = 79.86%
Oxygen = 20.14%
To calculate the empirical formula which is the simplest formula of the compound, we follow these steps:
> Express the mass percentages as the mass of the elements of the compound.
> Find the number of moles by dividing through by the atomic masses
> Divide by the smallest and either approximate to nearest whole number or multiply through by a factor.
> The ratio is the empirical formula of the compound.
Solution:
I O
% of elements 79.86 20.14
Mass (in g) 79.86 20.14
Moles(divide by
Atomic mass) 79.86/127 20.14/16
Moles 0.634 1.259
Dividing by
Smallest 0.634/0.634 1.259/0.634
1 2
The empirical formula is IO₂
Answer:
I could help you but I need to do it on a separate paper/document
Sugar is 51.16% oxygen because 41.86 + 6.98 = 48.84, minus that from 100 gets 51.16.
Answer:
Yes
Explanation:
Because mixture is made up of two or more types of atoms .
Molarity is the number of moles of solute in one liter of solution whereas molality is the number of moles of solute present in 1 kilo gram of solution.
Molarity is denoted by M and molality denoted by m
Mass of solution
Density of solution = 1.1 g /mL
d = 1.1 = (W_B + W_A) /V
V = 910.11 mL
molarity of solution is:
= 0.0433 /0.910 = 0.0474 M
Thus, moalrity of solution is 0.0474 M
