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Mademuasel [1]
2 years ago
8

When rubbing alcohol and water are at room temperature, which one boils first

Chemistry
2 answers:
Ugo [173]2 years ago
6 0

Answer:

rubbing alcohol

mylen [45]2 years ago
5 0

Answer:

alcohol

Explanation:

Alcohol has a lower boiling point

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The number of _______________ in the nucleus determines an element's atomic number. this number defines the name of the element,
AleksandrR [38]

The number of <u>protons</u> in the nucleus determines an element's atomic number.

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3 years ago
Which layer of soil in the diagram contains clay and other particles of rock but little humus ?
Ahat [919]
Im thinking a horizon 
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3 years ago
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Compare and contrast ionic and Covalent compounds​
Elden [556K]

Answer:

Ionic bonding occurs between atoms that have opposite needs for electrons (metals and nonmetals) and results in a transfer of electrons. Covalent bonding occurs between atoms that have similar needs for electrons (two nonmetals) and results in a sharing of electrons.

Explanation:

3 0
3 years ago
An isotope has 15 protons, 16 neutrons, and 15 electrons. What is the isotopic notation of the isotope
VikaD [51]

Answer:

^{31}_{15}P is the isotopic notation of the atom

Explanation:

The isotope notation is:

^a_bX

<em>Where a is the mass number = Number of protons + Number of neutrons</em>

<em>b is atomic number = Number of protons</em>

The atomic number define the nature of the atom, the element with atomic number = 15 is phosphorus, P:

^a_bP

a = 15 protons + 16 neutrons = 31

b = 15

^{31}_{15}P is the isotopic notation of the atom.

3 0
3 years ago
Arrange the following H atom electron transitions in order of decreasing wavelength of the photon absorbed or emitted:
Katyanochek1 [597]

The decreasing order of wavelengths of the photons emitted or absorbed by the H atom is : b → c → a → d

Rydberg's formula :

                                   \frac{1}{\lambda} = R_h (\frac{1}{n_1^2}-\frac{1}{n_2^2} ),

where  λ is the wavelength of the photon emitted or absorbed from an H atom electron transition from n_1 to n_2 and R_h = 109677 is the Rydberg Constant. Here n_1 and  n_2 represents the transitions.

(a) n_1 =2 to n_2 = infinity

            \frac{1}{\lambda} = 109677\times (\frac{1}{2^2}-\frac{1}{\infty^2}  ) = 109677/4     [since 1/infinity = 0] Therefore, \lambda = 4 / 109677 = 0.00003647 m

(b) n_1=4 to  n_2 = 20

           \frac{1}{\lambda} = 109677\times (\frac{1}{4^2}-\frac{1}{20^2}  ) = 6580.62

Therefore,  \lambda = 1 / 6580.62 = 0.000152 m

(c) n_1=3 to  n_2 = 10

          \frac{1}{\lambda} = 109677\times (\frac{1}{3^2}-\frac{1}{10^2}  ) = 11089.56

Therefore,  \lambda = 1 / 11089.56 = 0.00009 m

(d)  n_1=2 to  n_2 = 1

          \frac{1}{\lambda} = 109677\times (\frac{1}{2^2}-\frac{1}{1^2}  ) = - 82257.75

Therefore,  \lambda = 1 /82257.75  = - 0.0000121 m  

[Even though there is a negative sign, the magnitude is only considered because the sign denotes that energy is emitted.]

So the decreasing order of wavelength of the photon absorbed or emitted is b → c → a → d.

Learn more about the Rydberg's formula athttps://brainly.com/question/14649374

#SPJ4

8 0
1 year ago
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