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AVprozaik [17]
2 years ago
13

Rewrite the expression without using a negative exponent.

Mathematics
2 answers:
klasskru [66]2 years ago
7 0

Answer:

y²/2

Step-by-step explanation:

when an exponent is negative and is in the numerator, put it into the denominator and it will become positive

when an exponent is negative and is in the denominator, put it into the numerator and it will become positive

notka56 [123]2 years ago
4 0

Answer:

Step-by-step explanation:

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Which of the following is true of rounding the optimized solution of a linear program to an integer?
VashaNatasha [74]

Answer: Option 'c' is correct.

Step-by-step explanation:

Since we have given that

the optimized solution of a linear program to an integer as it does not affect the value of the objective function.

As if we round the optimized solution to the nearest integer, it does not change the objective function .

while it is not true that it always produces the most optimal integer solution or feasible solution.

Hence, Option 'c' is correct.

6 0
3 years ago
I NEED HELP PLEASE !!!!
Amiraneli [1.4K]

Answer:

NEVER INTERSECT

Hope this Helps

7 0
2 years ago
A right rectangular prism is packed with cubes of side length fraction 1 over 5 inch. If the prism is packed with 15 cubes along
Ann [662]

Given:

A right rectangular prism is packed with cubes of side length \dfrac{1}{5} inch.

Prism is packed with 15 cubes along the length, 6 cubes along the width, and 5 cubes along the height.

To find:

The volume of the prism

Solution:

Side length of each cube =\dfrac{1}{5} inch.

15 cubes along the length, so length of prism is

l=15\times \dfrac{1}{5}=3\text{ inches}

6 cubes along the width, so width of prism is

b=6\times \dfrac{1}{5}=\dfrac{6}{5}\text{ inches}

5 cubes along the height, so height of prism is

h=5\times \dfrac{1}{5}=1\text{ inch}

Now,

Volume of rectangular prism is

V=l\times b\times h

V=3\times \dfrac{6}{5}\times 1

V=\dfrac{18}{5}

V=\dfrac{3\times 5+3}{5}

V=3\dfrac{3}{5}\text{ cubic inches}

Therefore, the correct option is B.

7 0
3 years ago
Solve the system of equations. y = 6x - 27 y = 4x - 17
NeTakaya
Y=6x-27...........(1)
y=4x-17...........(2)

By comparison
6x-27=4x-17
=> 2x=10 => x=5
Substitute x=5 into (1)
y=6(5)-27=3
Check:
y=4(5)-17=3 as well.
5 0
2 years ago
Read 2 more answers
Let X1, X2 and X3 be three independent random variables that are uniformly distributed between 50 and 100.
sergejj [24]

Answer:

a) the probability that the minimum of the three is between 75 and 90 is 0.00072

b) the probability that the second smallest of the three is between 75 and 90 is 0.396

Step-by-step explanation:

Given that;

fx(x) = { 1/5 ; 50 < x < 100

              0, otherwise}

Fx(x) = { x-50 / 50 ; 50 < x < 100

                          1 ;   x > 100

a)

n = 3

F(1) (x) = nf(x) ( 1-F(x)^n-1

= 3 × 1/50 ( 1 - ((x-50)/50)²

= 3/50 (( 100 - x)/50)²

=3/50³ ( 100 - x)²

Therefore P ( 75 < (x) < 90) =  ⁹⁰∫₇₅ 3/50³ ( 100 - x)² dx

= 3/50³ [ -2 (100 - x ]₇₅⁹⁰

= (3 ( -20 + 50)) / 50₃

= 9 / 12500 = 0.00072

b)

f(k) (x) = nf(x)  ( ⁿ⁻¹_k₋ ₁) ( F(x) )^k-1 ; ( 1 - F(x) )^n-k

Now for n = 3, k = 2

f(2) (x) = 3f(x) × 2 × (x-50 / 50) ( 1 - (x-50 / 50))

= 6 × 1/50 × ( x-50 / 50) ( 100-x / 50)

= 6/50³ ( 150x - x² - 5000 )

therefore

P( 75 < x2 < 90 ) = 6/50³ ⁹⁰∫₇₅ ( 150x - x² - 5000 ) dx

= 99 / 250 = 0.396

3 0
2 years ago
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