Solving a polynomial inequation
Solving the following inequation:
(x - 8) (x + 1) > 0
We are going to find the sign both parts of the multiplication,
(x - 8) and (x + 1), have when
x < - 8
-8 < x < 1
1 < x
Then we know (x - 8) (x + 1) > 0 whenever (x - 8) (x + 1) is positive
We can see in the figure (x - 8) (x + 1) is positive when x < -8 and x > 1
Then
Answer:B
We can use the FOIL method to simplify.
= (3x – 1)(2x + 9)
= (3x * 2x) + (3x * 9) + (-1 * 2x) + (-1 * 9)
= 6x + 27x + (-2x) + (-9)
= 33x - 11
Hope This Helped! Good Luck!
You just need a calculator.
The answer is 3.1821
Source: A caluculator
Multiply denominator by whole number then add that number to the nominator. Which would be 5 times 1 plus 3. SO 5+3 IS 8 and you keep the denominator so the first one is 8/5
