Answer:
0.125 A
Explanation:
From the question given above, the following data were obtained:
Power (P) = 30 W
rms voltage (Vrms) = 240 V
rms Current (Irms) =?
The power in an electric circuit is given by the following equation:
Power (P) = current (I) × voltage (V)
With the above formula, we can obtain the rms current flowing through the bulb as shown below:
Power (P) = 30 W
rms voltage (Vrms) = 240 V
rms Current (Irms) =?
P = Irms × Vrms
30 = Irms × 240
Divide both side by 240
Irms = 30 / 240
Irms = 0.125 A
Thus, the rms current flowing through the light bulb is 0.125 A
You multiply the mass by the acceleration 82*7.5=615; that's what I would do
Answer:
length
Explanation:
used to measure outer dimensions of objects
Answer:
Explanation:
As given point p is equidistant from both the charges
It must be in the middle of both the charges
Assuming all 3 points lie on the same line
Electric Field due a charge q at a point ,distance r away
Where
- q is the charge
- r is the distance
-
is the permittivity of medium
Let electric field due to charge q be F1 and -q be F2
I is the distance of P from q and also from charge -q
⇒
F1
F2
⇒
F1+F2=
The ocean does not change temperature but it does lose some entropy ( he gives heat to melt the ice and to warm it to 3.70° C ).
I ) For the ice:
1 ) For melting the ice:
Q = m · Lf = 4.45 kg · 334 · 10³ J/kg = 1,486,300 J
Δ S = Q / T = 1,486,300 J / 273.15 K = 5.441 · 10³ J/K.
2 ) To warm the melted ice to 3.70° C:
Q = m c Δ T = 4.45 kg · 4,190 J / kgK · 3.70 K = 68,988.35 J
Δ S = m c ln( T2/ T1 ) = 4.45 kg · 4,190 J/kgK · ln ( 276.85 / 273.15 ) =
= 18,645.5 · ln ( 1.01354 ) = 18.645.5 · 0.013454 = 250.8692 J/K
II ) For the ocean:
Δ S = Q / T = ( - 68,988.35 + 1,486,300 ) / 276.85 = - 5,617.8 J/K
The net entropy change:
Δ S = ΔS ice + ΔS ocean = 5,441.1 + 250.8692 - 5,617.8 = 74.1692 J/K
Answer: 74 J/K.
