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3 years ago

Shawna is very knowledgeable about cars

Physics

1 answer:

maksim [4K]3 years ago

7 0

i think i know what your talking about and if i do then your answer is <u>unreliable</u>.

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While on a sailboat at anchor, you notice that 15 waves pass its bow every minute. The waves have a speed of 6.0 m/s . Part A Wh

Alchen [17]

Answer:

Distance between two adjacent wave crests = 24m

Explanation:

Distance= speed × time

Distance traveled by waves in 60 seconds (15 crests)= 15 × distance

15 × distance = 6,0 (meters/second) × 60 seconds

distance = (360 meters) / 15 = 24 meters (between two adyacent waves)

8 0

3 years ago

What is the term used to label the energy levels of electrons?

mel-nik [20]

Electron volts...........

4 0

3 years ago

A 200.0 g block rests on a frictionless, horizontal surface. It is pressed against a horizontal spring with spring constant 4500

kenny6666 [7]

Answer:

6 m/s

Explanation:

Given that :

mass of the block m = 200.0 g = 200 × 10⁻³ kg

the horizontal spring constant k = 4500.0 N/m

position of the block (distance x) = 4.00 cm = 0.04 m

To determine the speed the block will be traveling when it leaves the spring; we applying the work done on the spring as it is stretched (or compressed) with the kinetic energy.

i.e $\frac{1}{2} kx^2 = \frac{1}{2} mv^2$

$kx^2 = mv^2$

$4500* 0.04^2 = 200*10^{-3} *v^2$

$7.2 =200*10^{-3}*v^{2}$

$v^{2} =\frac{7.2}{200*10^{-3}}$

$v =\sqrt{\frac{7.2}{200*10^{-3}}}$

v = 6 m/s

Hence,the speed the block will be traveling when it leaves the spring is 6 m/s

5 0

3 years ago

A cheetah, which is the fastest land mammal, can accelerate at 9 m/s from rest to in 31 m/s. How long does

Anna007 [38]

31 m/s ÷ 9 m/s² = 3.44 s

Time = Change in velocity divided (÷) by acceleration.

8 0

3 years ago

The total consumption of electrical energy in the United States is about 1.0 1019 joules per year.

dexar [7]

Answer:

a) 316880878140.2895 Joules

b) 1056.26 Joules

c) 372.80103310622 km²

Explanation:

Energy consumption

$E=\frac{P}{t}\\\Rightarrow E=\frac{1\times 10^{19}}{365.25\times 24\times 60\times 60}\\\Rightarrow E=316880878140.2895\ W$

Average rate of electrical energy consumption is 316880878140.2895 Joules

Total population = 300 million

$E=\frac{316880878140.2895}{300\times 10^6}\\\Rightarrow E=1056.26\ J$

Each person consumes 1056.26 Joules.

Efficiency = 0.85

Power from Sun

$0.85\times 1000=850\ W/m^2$

Area

$\frac{316880878140.2895}{850}=372801033.10622\ m^2$

Converting to km²

$372801033.10622=\frac{372801033.10622}{1000\times 1000}=372.80103310622\ km^2$

Area required to collect the electrical energy used in the United States is 372.80103310622 km²

4 0

2 years ago

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Shawna is very knowledgeable about cars​

Shawna is very knowledgeable about cars