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Kruka [31]
3 years ago
5

To attend the football game, it costs $8 for parking plus $59 per ticket. If Bryan paid $362, how many tickets did he purchase?

Mathematics
1 answer:
MakcuM [25]3 years ago
3 0

Answer:6 tickets

Step-by-step explanation:

X= number of tickets

59x+8= 362

59x= 362-8

59x= 354

X= 354/59

X= 6

Bryan bought six tickets, hope this helps!!!!

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Volume of cone is given by the formula:

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Putting h = 6 and r = 9 in the formula, we get:

V=\frac{1}{3}\pi r^2 h\\V=\frac{1}{3}\pi (9)^2 (6)\\V=\frac{1}{3}\pi (486)\\V=162 \pi


D is the correct choice.

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What is the x-intercept of 6x-y=9​
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What is the factored form of the function f(x)=x^3+7x^2+8x−16?
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Answer:

(x-1) (x+4)^2

Step-by-step explanation:

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7 0
3 years ago
Dixie Showtime Movie Theaters, Inc., owns and operates a chain of cinemas in several markets in the southern U.S. The owners wou
WINSTONCH [101]

Answer:

Step-by-step explanation:

Hello!

You have the Data for three variables of interest:

"Weekly Gross Revenue"

"Television Advertising"

"Newspaper Advertising"

The owners of the Movie Theaters want to estimate the weekly gross revenue as a function of advertising expenditures.

For all asked regression the dependent variable will be Y: Weekly Gross Revenue

a)Using X: the amount of Television Advertising, as the independent variable, you have to test the simple linear regression.

The first step is to estimate the regression model

E(Yi)= α + βXi

Then ^Yi= a + bXi

Where "a" is the estimate of the intercept and "b" is the estimate of the slope.

Using a statistic software I've calculated the simple linear regression as:

a= -45.43

b= 40.06

^Yi= -45.43 + 40.06Xi

To test if there is a significant relationship between television advertising and weekly gross revenue you have to test the population slope of the regression, the hypotheses are:

H₀: β = 0

H₁: β ≠ 0

α: 0.05

You have two ways to test if the regression is significant, you either use a two-tailed t-test or a one-tailed F-test. They are two different distributions and test but you either one you can reach the same result.

I'll use the t-test for this item and the F-test for the later tests.

t= \frac{b-\beta }{Sb} ~ t_{n-2}

t_{H_0}= \frac{40.06-0}{14.64}= 2.74

The p-value for this test is 0.0339

Using the p-value approach the decision rule is:

If p-value ≤ α, the decision is to reject the null hypothesis.

If the p-value > α, the decision is to not reject the null hypothesis.

The p-value: 0.0339 is less than α: 0.05, the decision is to reject the null hypothesis.

The conclusion is that there is a significant relationship between television advertising and weekly gross revenue.

Looking at the estimated value of the slope, these two variables may have a direct relationship, i.e. every time the amount of television advertising is increased, the weekly gross revenue increases too. (This is only a supposition, without a propper hypothesis test you cannot conclude anything)

b) To know what % of the variation of the weekly gross revenue is explained by the model you have to calculate the coefficient of determination.

For item a) the coefficient is:

R²= 0.56

This means that 56% of the variability of the weekly gross revenue is explained by the amount of television advertisement under the estimated model: ^Yi= -45.43 + 40.06Xi

c) This time you have to develop a regression equation using two independent variables, be:

X₁: Amount of Television Advertising

X₂: Amount of Newspaper Advertising

The multiple regression model will be

E(Yi)= α + β₁X₁ + β₂X₂

α is the intercept ⇒ its estimator will be a

β₁ is the slope corresponding to X₁ ⇒ its estimator will be b₁

β₂ is the slope corresponding to X₂ ⇒ its estimator will be b₂

The estimated multiple regression model is ^Y= -42.57 + 22.40X₁ + 19.50X₂

The hypotheses for the overall regression are:

H₀: β₁ = β₂ = 0

H₁: At least one βi ≠ 0 ∀ i= 1, 2

α: 0.05

For this hypothesis test is best to use the F-test

F= \frac{MSreg}{MSerror}~~F_{DFreg;DFerror}

F_{H_0}= \frac{14215.57}{413.37}= 34.39

p-value: 0.0012

The p-value is less than α, the decision is to reject the null hypothesis.

Using a significance level of 5%, the overall regression is statistically significant.

For the single hypotheses I'll use the t-student and p-value approach:

1) Intercept

H₀: α = 0

H₁: α ≠ 0

α: 0.05

t_{H_0}= -1.49

p-value: 0.1961

The p-value is greater than the level of significance, the decision is to not reject the null hypothesis.

2) Slope for X₁

H₀: β₁ = 0

H₁: β₁ ≠ 0

α: 0.05

t_{H_0}= 3.16

p-value: 0.0252

The p-value is less than the significance level, the decision is to reject the null hypothesis.

Using a significance level of 5%, the regression is significant i.e. the amount of television advertising modifies the average weekly gross revenue.

3) Slope for X₂

H₀: β₂ = 0

H₁: β₂ ≠ 0

α: 0.05

t_{H_0}= 5.27

p-value: 0.0033

The p-value is less than the significance level, the decision is to reject the null hypothesis.

Using a significance level of 5%, the regression is significant, i.e. the amount of newspaper advertising modifies the average weekly gross revenue.

d) The corresponding coefficient of determination for the multiple regression is R²= 0.93

93% of the variability of the average weekly gross revenue is explained jointly by the amount of television advertisement and newspaper advertisement under the estimated model: ^Y= -42.57 + 22.40X₁ + 19.50X₂

e) and f)

Comparing the result in a) and c) you can say that both independent variables are good to explain the dependent variable.

Comparing both R², we can say that the amount of television advertisement alone isn't a good explanatory variable for the variability weekly gross revenue but together with the amount of newspaper advertisement it becomes a good explanatory variable.

I hope this helps!

7 0
3 years ago
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