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2 years ago

Which of the following are exterior angles? Check all that apply. ASAP please

Mathematics

2 answers:

bezimeni [28]2 years ago

7 0

It's 1,2 &3 I think... because the interior angles are all angles on the inside between adjacent sides

emmainna [20.7K]2 years ago

6 0

Your answer is 5 and 1.

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I will give you 10B points plus mark someone again for the Brainliest if you get this right.

Musya8 [376]

Answer:

Option D is the correct answer

Step-by-step explanation:

$(3 {m}^{ - 4} )^{3} (3 {m}^{5} ) \\ \\ = {3}^{3} {m}^{ - 4 \times 3} \times 3 {m}^{5} \\ \\ = 27 \times 3 \times {m}^{ - 12 + 5} \\ \\ = 81 {m}^{ - 7} \\ \\ = \frac{81}{ {m}^{7} }$

8 0

3 years ago

Read 2 more answers

If A is nonsingular, then (AT )-1 =(A-1) T . (a) Verify this theorem for 2 × 2 matrices

kipiarov [429]

Answer:

Verified

Step-by-step explanation:

Let the 2x2 matrix A be in the form of:

$\left[\begin{array}{cc}a&b\\c&d\end{array}\right]$

Where det(A) = ad - bc # 0 so A is nonsingular:

Then the transposed version of A is

$A^T = \left[\begin{array}{cc}a&c\\b&d\end{array}\right]$

Then the inverted version of transposed A is

$(A^T)^{-1} = \frac{1}{ad - cb} \left[\begin{array}{cc}a&-c\\-b&d\end{array}\right]$

The inverted version of A is:

$A^{-1} = \frac{1}{ad - bc}\left[\begin{array}{cc}a&-b\\-c&d\end{array}\right]$

The transposed version of inverted A is:

$(A^{-1})^T = \frac{1}{ad - bc}\left[\begin{array}{cc}a&-c\\-b&d\end{array}\right]$

We can see that

$(A^T)^{-1} = (A^{-1})^T$

So this theorem is true for 2 x 2 matrices

3 0

3 years ago

In integers how to know if minus (-) 1 upon 2 is greater or minus (-) 1 is greater???

kogti [31]

Answer:

1/2 is 0.5 so -1/2=-0.5

-0.5 is greater than -1

use a number line

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Find the first of three consecutive even integers if the sum of the first and second is 15 less than 3 times the third.

lilavasa [31]

Answer:

<em>First even integer: 6</em>

Step-by-step explanation:

<u>Inequalities</u>

Assume x is the first even integer. The next integer is x+2, and the last integer ix x+4.

The condition states that the sum of the first and the second number is 15 less than three times the third. This takes us to the inequality:

$x+x+2$

Operating:

$2x+2$

Subtracting 2 and 2x:

$0$

Simplifying:

$0$

Solving:

x>5

There are infinitely many solutions. For example, for x=6 (first even number into the solution interval):

First integer: 6

Second integer: 8

Third integer: 10

There are other solutions, like 20,22,24 but the first set is 6,8,10.

4 0

3 years ago

Picture provided help!

weqwewe [10]

Answer:

A -60i - 14j

Step-by-step explanation:

u = -9i + 8j

v = 7i + 5j

2u = 2(-9i + 8j) = -18i + 16j

6v = 6(7i + 5j) = 42i + 30j

2u - 6v

(-18i + 16j) - (42i + 30j)

(-18i - 42i) + (16j-30j)

-60i - 14j

5 0

3 years ago