Answer:
2.5 second
Step-by-step explanation:
The equation is missing in the question.
The equation is, 
, where 'h' is the height and 't' is time measured in second.
Now we know to reach its maximum height, h in t seconds, the derivative of h with respect to time t is given by :
Now the differentiating the equation with respect to time t, we get
For maximum height,
So, 
Therefore, the ball takes 2.5 seconds time to reach the maximum height.
Answer:
1) 
2) 
Step-by-step explanation:
Please ignore the squiggle in the middle of the page.
Please mark brainliest when you’re able :)
Set up the given triangle on x-y coordinates with right angle at (0,0). So the two vertices are at (5,0) and (0,2
![sqrt{x} n]{3}](https://tex.z-dn.net/?f=sqrt%7Bx%7D%20n%5D%7B3%7D%20)
)
let (a,0) and (0,b) be two vertices of the<span> equilateral triangle. So the third vertex must be at </span>
for a pt (x,y) on line sx+ty=1, the minimum of
equals to
smallest value happens at
so area is
hence m=75, n=67, p=3
m+n+p = 75+67+3 = 145
Would it be a correct me if im wrong
Length(l)= 2w
Width(w)= w
Area(A) = l*w
A= 128 ft²
128= l*w
128= (2w)w
2w²= 128
w²= 64
w=√64= 8 ft
w= 8 ft
length(l)= 2w
l=2(8)
l=16 ft
P= 2l+2w
P=2(16)+2(8)= 32+16= 48ft
P= 48ft
Answer:
The Perimeter of this rectangle is 48 feet.
Leave any questions you still have in the comments below please! Thank you! Hope this helped! :)
