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3 years ago

Patrick is hanging supports on the

Mathematics

1 answer:

Slav-nsk [51]3 years ago

6 0

Answer:

Step-by-step explanation:

straight lines are always 180.

$180=125+x\\180-125=125+x-125\\55=x$

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Tanisha plants 2/3 of her garden with flowers.She covers 1/4 of this part of the garden with roses.What part of her whole garden

Talja [164]

Answer:

$\frac{1}{6}$

Step-by-step explanation:

We can find this by multiplying the two-thirds of Tanisha's garden by one-fourth, which is $\frac{2}{3}*\frac{1}{4}=\frac{1}{6}$ .

8 0

3 years ago

Simplify the expression shown below: (a^3b^12c^2)^2(a^5c^2)^3(b^5c^4)^0

NemiM [27]

= a^21b^24c^10
use the product rules for each set of () then multiply them together. when multiplying variables with exponents you just add them together like for a^3 * a^5 = a^8. (a^3 b^12 c^2)^2 = (a^6 b^24 c^4)

4 0

3 years ago

I need help with this please

andrezito [222]

Answer:

1988920000000000

Step-by-step explanation:

1.98892 x 1000000000000000 (15 zeros)

The upper number (in this case 15) indicates the amount of zeros after the 1 (10 is 10^1, 100 is 10^2)

7 0

3 years ago

In 2000, the circulation of a local newspaper was 3,250. In 2001, its circulation was 3,640. In 2002, the circulation was 4,100.

vodka [1.7K]

Percent increase from 2000 to 2001 is 12% and from 2001 to 2002 is 12.6%. Thus period of 2001 to 2002 has higher increase percentage.

Solution:

Given that,

Total circulation of local newspaper in 2000 = 3250

Total circulation of local newspaper in 2001 = 3640

Total circulation of local newspaper in 2002 = 4100

Finding percent of increase in the newspaper’s circulation from 2000 to 2001:

$\text { Percent increase from } 2000 \text { to } 2001=\frac{\text { change in circulation from 2001 - 2000 }}{\text { circulation in } 2000} \times 100$

$\begin{array}{l}{=\frac{3640-3250}{3250} \times 100} \\\\ {=\frac{390}{3250} \times 100=12 \%}\end{array}$

Finding percent of increase in the newspaper’s circulation from 2001 to 2002:

$\begin{array}{l}{\text { Percent increase from } 2001 \text { to } 2002=\frac{\text { change in circulation }}{\text {circulation in } 2001} \times 100} \\\\ {=\frac{4100-3640}{3640} \times 100} \\\\ {=\frac{460}{3640} \times 100=12.6 \%}\end{array}$

As we can see 12% < 12.6%

So period of 2001 to 2002 has higher increase percentage.

7 0

3 years ago

Suppose you know three minimum,lower quartile,median, upper quartile, and maximum values for a set of data. Explain how to creat

timurjin [86]

Answer: First, draw and label a number line. Then plot the five values that are given above the line. Draw a box from the lower quartile to the upper quartile, with a line dividing it at the median. Then draw lines from the minimum and maximum values connecting to the box to form the whiskers.

3 0

3 years ago