To check for continuity at the edges of each piece, you need to consider the limit as 
approaches the edges. For example,
has two pieces, 
and 
, both of which are continuous by themselves on the provided intervals. In order for 
to be continuous everywhere, we need to have
By definition of , we have 
, and the limits are
The limits match, so is continuous.
For the others: Each of the individual pieces of 
are continuous functions on their domains, so you just need to check the value of each piece at the edge of each subinterval.
You could subsitute g(x) for x in f(x) and if you get x as a result, then that is indeed the inverse
ex
if
f(x)=x-2
the inverse which is g(x) is
g(x)=x+2 because if you did
f(g(x)) then you would get
f(g(x))=(2+x)-2=2-2+x=x
Answer:
The second one (3x, 9x)
Step-by-step explanation:
Like terms are the terms that either have the same variable or have no variable.
Answer:
The inquality is always false i think..
Step-by-step explanation:
I’m not 100% sure but i think ur answer rn is correct don’t check the second box
