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3 years ago

What is (-8) third power

Mathematics

2 answers:

Aleks04 [339]3 years ago

6 0

-512.

Type negative 8 to the third power in google. It really is the answer. :)

Ierofanga [76]3 years ago

5 0

The answer is negative 2

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How do i write and solve for this inequality

ExtremeBDS [4]

9514 1404 393

Answer:

-7/4 < x < 8

Step-by-step explanation:

The value of y can be determined from the sum of the angles, so you know each of the angles exactly. That means you know the ratio of side lengths exactly, which lets you solve for x exactly.

Setting that aside, we observe that angle C is greater than angle A, so side AB will be longer than side BC.

3x +15 > 4x +7

8 > x . . . . . . . . . . subtract 3x+7

We also know that the lengths of these sides must be positive. Since BC is the shorter side, we require ...

4x +7 > 0

4x > -7

x > -7/4

So, the allowable values of x are ...

-7/4 < x < 8

_____

<em>More complete solution</em>

If we read the figure correctly, the sum of angles is ...

(2y +12) +(4y +12) +(y -18) = 180

7y +6 = 180

y = (180 -6)/7 = 24 6/7°

Then (in degrees) ...

∠A = 2(24 6/7) +12 = 61 5/7, and ∠C = 4(24 6/7) +12 = 111 3/7

The Law of Sines tells us ...

AB/sin(C) = BC/sin(A)

sin(A)(3x +15) = sin(C)(4x+7)

x(4sin(C) -3sin(A)) = 15sin(A) -7sin(C)

x = (15sin(A) -7sin(C))/(4sin(C) -3sin(A))

x ≈ 6.1872652

4 0

3 years ago

Machine A can complete a certain job in x hours. Machine B can complete the same job in y hours. If A and B work together at the

scZoUnD [109]

Answer:

$\frac{y}{x+y}$

Step-by-step explanation:

The required answer is the rate at which Machine A works when the two machines are combined.

Note: the rate of doing work is express as

$rate=\frac{1}{time taken} \\$

Hence we can conclude that Machine A working rate is

$machine A=\frac{1}{x} \\$ and machine B working rate is

$machine B=\frac{1}{y} \\$

When the two machine works together, the effective working rate is

$\frac{1}{x}+\frac{1}{y}\\\frac{xy}{x+y}\\$

The fraction of the work that Machine B will not have complete because of Machine A help is the total work done by machine A

Hence the fraction of work done by A is expressed as

$\frac{1}{x}*combine working rate$

$\frac{1}{x}*\frac{xy}{x+y}\\\frac{y}{x+y} \\$

Hence the fraction of the work that Machine B will not have complete because of Machine A help is the total work done by machine A is $\frac{y}{x+y} \\$