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Aloiza [94]
3 years ago
13

The students at Southern Junior high School are divided into four home rooms. Benjamin just moved into the school district and w

ill be randomly assigned to one home room

Mathematics
1 answer:
andre [41]3 years ago
5 0

Answer:

A 4 side dice.

Step-by-step explanation:

Benjamin has 4 possible homerooms with the same probability. This means that every homeroom has a 1/4 = 0.25 (or 25%) probability of getting chosen.

You could emulate this situation with a 4 sided dice (are like little pyramids) where each side of the dice would represent the selection of one of the homerooms.

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Plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz
Andrei [34K]

Answer:

Circle 1=6x+2y

Rectangle 4 = 3x+y

Circle 4 = 5x

Step-by-step explanation:

4x+3y and 2x-y can be added to find result for the circle.

Let C1 represent circle 1

4x+3y+2x-y=C1\\

Combining\:like\:terms\\

4x+2x+3y-y=C1

6x+2y=C1

So, The result is: C1=6x+2y

Now, We need to solve:

Let R1 represent rectangle 4

x+4y + R1 = 4x+5y

R1=4x+5y-(x+4y)

R1=4x+5y-x-4y

R1=4x-x+5y-4y

R1=3x+y

So, Solving x+4y + R1 = 4x+5y, We get R1 = 3x+y

Now, We need to solve the equation:

Let C4= Circle 4

2x-y+3x+y=C4

Combining the like terms

2x+3x-y+y=C4

5x=C4

So, Solving 2x-y+3x+y=C4 we get C4 = 5x

7 0
3 years ago
Savannah runs a day care center. Of the 12 children at the day care center, 3 of them are
sertanlavr [38]

Answer:

\frac{1}{4}

Step-by-step explanation:

3 out of 12 children at the day care center are 5-year-olds. So, the probability of a randomly selected child being a five-year old is \frac{3}{12}, or \frac{1}{4}.

6 0
3 years ago
Plz help asap......................................
ziro4ka [17]

Option B:

Law of cosine, two sides and the included angle are known.

Solution:

Let us first know the law of cosines and law of sines.

Law of cosine:

If we know the sides a, b and the included angle θ, then we can find the third side c. This is known as the law of cosine.

c^2=a^2+b^2-2abcos\theta

Law of sine:

The sides of a triangle are to one another  in the same ratio as the sines of their opposite angles.

$\frac{a}{sinA} =\frac{b}{sinB} =\frac{c}{sinC}

Given ∠P and the sides r, q are known.

<u>To find the value of p:</u>

Option A: Law of cosines, all sides are known.

It is false by the above definition of law of cosine.

Option B: Law of cosine, two sides and the included angle are known.

It is true by the above definition of law of cosine.

Option C: Law of sines, all sides are known.

It is false, because one angle is given in question.

Option D: Law of sines, two angles and the included side are known.

It is false, because two angles are not given.

Option B is the correct answer.

Hence the answer is "Law of cosine, two sides and the included angle are known".

7 0
3 years ago
The square of a number, x, is 16 less than eight times the number. What is the number? Type the correct answer in the box. Use n
liraira [26]

Given :

The square of a number, x, is 16 less than eight times the number.

To Find :

The value of x .

Solution :

The mathematical equation with all given data is :

x^2=8x-16\\\\x^2-8x+16=0\\\\x^2-4x-4x+16=0\\\\x(x-4)-4(x-4)=0\\\\(x-4)^2=0\\\\x=4

Therefore , the value of x is 4 .

Hence , this is the required solution .

3 0
3 years ago
PLEASE HELP AND SHOW WORK PLEASE.
Vaselesa [24]

Inequalities help us to compare two unequal expressions. There exists no solution to the given set of inequalities.

<h3>What are inequalities?</h3>

Inequalities help us to compare two unequal expressions. Also, it helps us to compare the non-equal expressions so that an equation can be formed. It is mostly denoted by the symbol <, >, ≤, and ≥.


The given Inequalities can be solved as,

5 - x > 7

-x > 7 - 5

-x > 2

x < -2

2x + 3 ≥ 13

2x ≥ 10

x ≥ 5

As per the solution of the two inequalities, the value of x should be less than -2 but at the same time, it should be more than or equal to 5, which is impossible. Thus, there is no solution for the given inequalities.

This can be confirmed by graphing the two inequalities, as shown below. Since there is no area in common between the two inequalities, there exists no solution to the given set of inequalities.

Learn more about Inequality:

brainly.com/question/19491153

#SPJ1

4 0
3 years ago
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