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Gennadij [26K]
3 years ago
6

Plz help asap......................................

Mathematics
1 answer:
ziro4ka [17]3 years ago
7 0

Option B:

Law of cosine, two sides and the included angle are known.

Solution:

Let us first know the law of cosines and law of sines.

Law of cosine:

If we know the sides a, b and the included angle θ, then we can find the third side c. This is known as the law of cosine.

c^2=a^2+b^2-2abcos\theta

Law of sine:

The sides of a triangle are to one another  in the same ratio as the sines of their opposite angles.

$\frac{a}{sinA} =\frac{b}{sinB} =\frac{c}{sinC}

Given ∠P and the sides r, q are known.

<u>To find the value of p:</u>

Option A: Law of cosines, all sides are known.

It is false by the above definition of law of cosine.

Option B: Law of cosine, two sides and the included angle are known.

It is true by the above definition of law of cosine.

Option C: Law of sines, all sides are known.

It is false, because one angle is given in question.

Option D: Law of sines, two angles and the included side are known.

It is false, because two angles are not given.

Option B is the correct answer.

Hence the answer is "Law of cosine, two sides and the included angle are known".

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Right triangle ABC and its image, triangle A'B'C' are shown in the image attached.
AlladinOne [14]

Answer:

See explanation

Step-by-step explanation:

Triangle ABC ha vertices at: A(-3,6), B(0,-4) and (2,6).

Let us apply 90 degrees clockwise about the origin twice to obtain 180 degrees clockwise rotation.

We apply the 90 degrees clockwise rotation rule.

(x,y)\to (y,-x)

\implies A(-3,6)\to (6,3)

\implies B(0,4)\to (4,0)

\implies C(2,6)\to (6,-2)

We apply the 90 degrees clockwise rotation rule again on the resulting points:

\implies (6,3)\to A''(3,-6)

\implies (4,0)\to B''(0,-4)

\implies (6,-2)\to C''(-2,-6)

Let us now apply 90 degrees counterclockwise  rotation about the origin twice to obtain 180 degrees counterclockwise rotation.

We apply the 90 degrees counterclockwise rotation rule.

(x,y)\to (-y,x)

\implies A(-3,6)\to (-6,-3)

\implies B(0,4)\to (-4,0)

\implies C(2,6)\to (-6,2)

We apply the 90 degrees counterclockwise rotation rule again on the resulting points:

\implies (-6,-3)\to A''(3,-6)

\implies (-4,0)\to B''(0,-4)

\implies (-6,2)\to C''(-2,-6)

We can see that A''(3,-6), B''(0,-4) and C''(-2,-6) is the same for both the 180 degrees clockwise and counterclockwise rotations.

7 0
3 years ago
SOLVE ASAP!!!
Karolina [17]
4s-3s=2 and if you were to solve this you would combine the s and get 1s so 1s=2
7 0
3 years ago
Read 2 more answers
PLEASE HELP! 35 POINTS!!
Butoxors [25]
The answer to this is

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we can switch the order because the negatives cancel

choice A is correct
choice B is wrong because it is flipped one but not the other
chocies C is correct

6 0
3 years ago
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Enter the equation of the line in slope-intercept form.
likoan [24]

Equation parallel to y = -x is y=-x+k

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Equation is y = -x + 11.5

3 0
3 years ago
1. Find the value of x.<br><br> A. 90<br> B. 80<br> C. 60<br> D. 45
tia_tia [17]

Answer:

A 90

Step-by-step explanation:

multiple ways to prove this.

e.g. since the angle between the two lines from the center of the circle to the 2 tangent touching points is 90 degrees (that is the meaning of these 90 degrees here as the angle of the circle segment defined by the 2 tangent touching points and the circle center), the tangents have the same "behavior" as tan and cot = the tangents at the norm circle at 0 and 90 degrees. they hit each other outside of the circle again at 90 degrees.

another way

imagine the two right triangles of the tangents crossing point to the circle center and the tangent/circle touching points.

the Hypotenuse of each triangle is cutting the 90 degree angle of the circle segment exactly in half (due to the symmetry principle). so the angle between radius side and Hypotenuse is 90/2 = 45 degrees.

that means also the angle of such a right triangle at the tangent crossing point is 45 degrees (as the sum of all angles in a triangle must be 180, we have the remainder of 180 - 90 - 45 = 45 degrees).

the angles of both right triangles at that point are the same, and so we can add 45+45 = 90 degrees for the total angle at the tangent crossing point.

8 0
3 years ago
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