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Setler [38]
3 years ago
10

Find the equation of a circle with a center at (0, -4) and a point on the circle is (6, 0).

Mathematics
1 answer:
EastWind [94]3 years ago
8 0

Answer:

x^2 + ( y + 4)^2 = 52

Step-by-step explanation:

Equation of circle with center (a , b) and radius, r is :

(x -a)^2 + ( y -b)^2 = r^2

Given :  a = 0 , b = - 4

Step 1 : Find the radius.

       Given ( 6 , 0 ) lies on the circle. Therefore the distance between the center (0 , - 4) of the circle and ( 6 , 0 ) gives the radius of the circle.

   r = \sqrt{( 0 - 6)^2 + ( -4 - 0)^2} \\\\

     = \sqrt{ 36 + 16 } \\\\= \sqrt{52}

Step 2 : Equation of circle.

  (x - 0)^2 + (y -( - 4))^2 = (\sqrt{52})^2\\\\x^2 + ( y+ 4)^2 = 52

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Explanation:
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