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3 years ago

Order the terms p2, p4, p3, and p in a descending powers of p

Mathematics

1 answer:

maksim [4K]3 years ago

8 0

It goes from p4,p3,p2 and p. Its in descending order, which means going down.

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The first step in solving 3.17 t - 2.431 = 5.06 is to divide both sides of the equation by 3.17. TrueFalse

Pavlova-9 [17]

Answer:

False

Step-by-step explanation:

$3.17t - 2.431 = 5.06 \\ 3.17t = 5.06 + 2.431 \\ 3.17t = 7.491 \\ \frac{3.17t}{3.17} = \frac{7.491}{3.17} \\ t = 2.363$

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3 years ago

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The following section is a statement from the rental agreement Tim signed when he rented his car this past weekend.

vitfil [10]

Answer:

b. $31.44

Step-by-step explanation:

The tank holds 11.75 gallons. Tim will need to get half of this amount to bring the tank back up to half full; this is

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The gas costs $4.50 per gallon; this means the cost is

5.875(4.50) = 26.4375 ≈ 26.44.

There is also a $5 refueling charge; this makes the total cost

26.44+5 = 31.44

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3 years ago

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Please help ! This is due today .

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If alpha and beta are the zeroes of the polynomial 6x2+x-2 find the value og alpha/beta + beta/alpha

castortr0y [4]

$6x^2+x-2=6x^2+4x-3x-2=2x(3x+2)-1(3x+2)\\\\=(3x+2)(2x-1)\\\\3x+2=0\to x=-\frac{2}{3}\\\\2x-1=0\to x=\frac{1}{2}\\\\\alpha=-\frac{2}{3};\ \beta=\frac{1}{2}\\\\\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{-\frac{2}{3}}{\frac{1}{2}}+\frac{\frac{1}{2}}{-\frac{2}{3}}=-\frac{2}{3}\cdot\frac{2}{1}-\frac{1}{2}\cdot\frac{3}{2}=-\frac{4}{3}-\frac{3}{4}\\\\=-\frac{16}{12}-\frac{9}{12}=-\frac{25}{12}=-2\frac{1}{12}$

$use\ Vieta's\ formula:\\\\\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{\alpha^2+\beta^2}{\alpha\beta}=\frac{\alpha^2+2\alpha\beta+\beta^2-2\alpha\beta}{\alpha\beta}=\frac{(\alpha+\beta)^2-2\alpha\beta}{\alpha\beta}=\frac{(\alpha+\beta)^2}{\alpha\beta}-2\\\\\alpha+\beta=\frac{-b}{a};\ \alpha\beta=\frac{c}{a}\\\\\frac{(\alpha+\beta)^2}{\alpha\beta}-2=\frac{\left(\frac{-b}{a}\right)^2}{\frac{c}{a}}-2=\frac{b^2}{a^2}\cdot\frac{a}{c}-2=\frac{b^2}{ac}-2$

$6x^2+x-2\\\\a=6;\ b=1;\ c=-2\\\\\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{1^2}{6\cdot(-2)}-2=\frac{1}{-12}-2=-2\frac{1}{12}$

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3 easy questions

Tasya [4]

It is p, as x. get it?

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