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3 years ago

I am offline can you please also help in this

Mathematics

1 answer:

Alona [7]3 years ago

4 0

Answer: $x^2+\frac{11}{4}x+\frac{3}{2}$

Step-by-step explanation:

Use FOIL:

$x^2+\frac{3}{4} x+\frac{4}{2} x+\frac{12}{8}$

$x^2+\frac{3}{4} x+\frac{8}{4}x+\frac{12}{8} \\$ Make 3/4x and 4/2x have the same denominator

$x^2+\frac{11}{4}x+\frac{12}{8}$ Add like terms

$x^2+\frac{11}{4}x+\frac{3}{2}$ Simplify

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Consider the sequence of numbers: 3/8, 3/4, 1 /18, 1 1/2, 1 7/8

vredina [299]

Question:

Consider the sequence of numbers: $\frac{3}{8}, \frac{3}{4}, 1\frac{1}{8}, 1\frac{1}{2}, 1\frac{7}{8}$

Which statement is a description of the sequence?

(A) The sequence is recursive, where each term is 1/4 greater than its preceding term.

(B) The sequence is recursive and can be represented by the function

f(n + 1) = f(n) + 3/8 .

(D) The sequence is arithmetic and can be represented by the function

f(n + 1) = f(n)3/8.

Answer:

Option B:

The sequence is recursive and can be represented by the function

$f(n + 1) = f(n) + \frac{3}{8} .$

Explanation:

A sequence of numbers are

$\frac{3}{8}, \frac{3}{4}, 1\frac{1}{8}, 1\frac{1}{2}, 1\frac{7}{8}$

Let us first change mixed fraction into improper fraction.

$\frac{3}{8}, \frac{3}{4}, \frac{9}{8}, \frac{3}{2}, \frac{15}{8}$

To find the pattern of the sequence.

To find the common difference between the sequence of numbers.

$\frac{3}{4}-\frac{3}{8}=\frac{6}{8}-\frac{3}{8}= \frac{3}{8}$

$\frac{9}{8}-\frac{3}{4}=\frac{9}{8}-\frac{6}{8}= \frac{3}{8}$

$\frac{3}{2}-\frac{9}{8}=\frac{12}{8}-\frac{9}{8}= \frac{3}{8}$

$\frac{15}{8}-\frac{3}{2}=\frac{15}{8}-\frac{12}{8}= \frac{3}{8}$

Therefore, the common difference of the sequence is 3.

That means each term is obtained by adding $\frac{3}{8}$ to the previous term.

Hence, the sequence is recursive and can be represented by the function $f(n + 1) = f(n) + \frac{3}{8} .$

3 0

3 years ago

The drama club is selling T-shirts and caps to raise money for a spring trip. The caps sell for $5.00 each, and the T-shirts sel

Zinaida [17]

The required inequality is $5x+10y\geq 500$

<em><u>Solution:</u></em>

Given that,

Cost of 1 cap = $ 5

Cost of 1 t-shirt = $ 10

Let "x" be the number of caps sold

Let "y" be the number of t-shirts sold

The drama club needs to raise at least $500.00 for the trip

Based on this information, we can frame a inequality as:

number of caps sold x cost of 1 cap + number of shirts sold x cost of 1 shirt $\geq$ 500

Which means,

$x \times 5 + y \times 10\geq 500\\\\5x + 10y\geq 500$

Here we used "greater than or equal to" symbol , because club needs to raise at least $ 500

They can raise 500 or more than $ 500 also

Thus the required inequality is $5x+10y\geq 500$

8 0

3 years ago

a circle with a circumference of 6 has an arc with a 20 degree central angle.What is the length of the arc

alex41 [277]

Answer:

2.094395 ft

Step-by-step explanation:

7 0

3 years ago

Please help Evaluate this equation!!

lozanna [386]

Answer:

1.)-8

2.)-5

3.)4

Step-by-step explanation:

So, the function f(x)=3x-5

The questions say "If you were to substitute these numbers what answer would you get?"

Understanding this,

First question is with x=-1

f(-1)=3(-1)-5

f(-1)=-3-5=-8

_____________________________________

f(0)=3(0)-5

f(0)=0-5=-5

_____________________________________

f(3)=3(3)-5

f(3)=9-5=4

6 0

3 years ago

Please help soon! Thanks! Solve for x

EastWind [94]

Answer:

$x=30^{\circ}$

Step-by-step explanation:

Looking at $\triangle LMN$ :

$\angle NML = 180 - (90+45)$ (angle sum of triangle is $180^{\circ}$ )

$=45^{\circ}$

Looking at $\triangle KNM$ :

$\angle KNM = 180-105$ (angle of straight is $180^{\circ}$ )

$=75^{\circ}$

$\angle KNM + \angle NKM + \angle KMN = 180$ (angle sum of triangle is $180^{\circ$ )

$75+2x+45 = 180$

$2x+120 = 180$

$2x=60$

$x=30^{\circ}$

Hope this helps :)

8 0

3 years ago