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lutik1710 [3]
3 years ago
9

Diego is thinking of two positive numbers. He says, 'If we triple the first number and double the second number, the sum is 34.'

Diego then says, 'If we take half of the first number and double the second, the sum is 14.' Answer the questions in the table to model Diego's problem. Let `x` equal the first number and `y` equal the second number.
Mathematics
1 answer:
UNO [17]3 years ago
8 0

1st number: 0

2nd number: 17

Answer

Step-by-step explanation:

3x+2y=34 x is the first number, y is the second.

1/2x+2y=34 multiply each number by two to get rid of the integer by the variable x.

x+4y=68 solve for x.

x=68-4y add this into the first equation to solve for variable y.

3(68-4y)+2y=34 solve for y.

204-10y=34

-10y= -170

y=17

now to solve for x

x= 68-4(17)

x= 0

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3 years ago
I need help I really don't get this problem....
Anton [14]
The answer is 12,288
5 0
4 years ago
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AnnZ [28]

Answer:

12-{16-(5×2)}²

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8 0
3 years ago
How do I solve this?
pishuonlain [190]
Good morning! So, what this question wants us to do is find each y value given its x value. Without the function it gives us already, this would be pretty difficult.
It gives us a function rule of y=2x+3. This means that we need to plug in each x value into the equation and solve for y. Let’s work on these first three.

y=2x+3} x=-4
y=2(-4)+3
y=-8+3
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So, if x=-4, then y=-5.

y=2x+3} x=-2
y=2(-2)+3
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Try out the last one, and if you have any questions, comment below! Here are some extra x values if you need more practice.
Using the same function rule, y=2x+3, try to find the y value if x=-6, x=-3, x=5, or x=6.
8 0
3 years ago
In the right triangle below, tanA = 0.45. What is the approximate length of AB?
kodGreya [7K]

Answer with Step-by-step explanation:

We are given that:

tanA = 0.45

tanA= \dfrac{Perpendicular}{Base}

      =  \dfrac{BC}{AC}

⇒  \dfrac{BC}{AC}=0.45

⇒  \dfrac{9}{AC}=\dfrac{45}{100}

⇒  \dfrac{9}{AC}=\dfrac{9}{20}

⇒  AC= 20

Hence, by pythagoras theorem

AB²=AC²+BC²

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⇒  AB=21.9 units

Hence,  the approximate length of AB is:

22 units

7 0
3 years ago
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