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Ugo [173]
3 years ago
13

Apply the distributive property to create an equivalent expression. (7−4n)⋅6= ?

Mathematics
1 answer:
AleksandrR [38]3 years ago
5 0

Answer:

<h2>(7 - 4n) · 6 = 42 - 24n</h2>

Step-by-step explanation:

The distributive property: <em>a(b - c) = ab - ac</em>

(7 - 4n) · 6 = (7)(6) - (4n)(6) = 42 - 24n

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The distance between B and C
alina1380 [7]

Answer:

The answer is

<h2>\sqrt{13}  \:  \: or \:  \: 3.6055 \:  \: units</h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

d =  \sqrt{( {x1 - x2})^{2} +  ({y1 - y2})^{2}  }  \\

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

B ( 3 , 1 ) and C( 6 , 3)

The distance between them is

|BC|  =  \sqrt{( {3 - 6})^{2}  +  ({1 - 3})^{2} }  \\  =  \sqrt{ ({ - 3})^{2}  + ( { - 2})^{2} }  \\  =  \sqrt{9 + 4}

We have the final answer as

\sqrt{13}  \:  \: or \:  \: 3.6055 \:  \: units

Hope this helps you

5 0
3 years ago
Cody was 165cm, {cm}165cm tall on the first day of school this year, which was 10% taller than he was on the first day of school
strojnjashka [21]

Answer:

Cody was 148.5cm on the first day of school last year.

Step-by-step explanation:

10% = 0.1

165 x 0.1 = 16.5

165 - 16.5 = 148.5

8 0
3 years ago
Read 2 more answers
What is 36,100 dived by 36,789
Stolb23 [73]
36100/36789=0.9812715757427492
3 0
3 years ago
Read 2 more answers
A carpool service has 2,000 daily riders. A one-way ticket costs $5.00. The service estimates that for each $1.00 increase to th
solmaris [256]

Answer:

Total number of riders that ride on carpool daily = 2000

Total Cost of one way ticket = $ 5.00

Total Amount earned if 2000 passengers rides daily on carpool = 2000 × 5

                                                                                                            = $10,000

If fare increases by $ 1.00

New fare = $5 + $1    

               = $6

Number of passengers riding on carpool = 2,000 - 100 = 1,900

If 1,900 passengers rides on carpool daily , total amount earned ,if cost of each ticket is $ 6 = 1900 × $6 = $11400

As we have to find the inequality which represents the values of x that would allow the carpool service to have revenue of at least $12,000.

For $ 1 increase in fare = (2,000 - 1 × 100) passengers

For $ x increase in fare, number of passengers = 2,000 - 100·x

                                                         = (2,000 - 100·x) passengers

New fare = 5 + x

New Fare × Final Number of passengers ≥ 12,000

(5+x)·(2,000 - 100 x) ≥ 12,000

5 (2,000 - 100 x) + x(2,000 - 100 x) ≥ 12,000

10,000 - 500 x + 2,000 x - 100 x² ≥ 12,000

100 - 5 x + 20 x - x² ≥ 120

- x² + 15 x +100 - 120 ≥ 0

-x² + 15 x -20 ≥ 0

x² - 15 x + 20 ≤ 0

⇒ x = 1.495

x ≥ $ 1.495, that is if we increase the fare by this amount or more than this the revenue will be at least 12,000 or more .

Also, f'(x) = 0 gives x = 7.5

⇒ The price of a one-way ticket that will maximize revenue is $7.50

7 0
3 years ago
I need help, someone please explain. I don't need the answers i just don't get it.
shepuryov [24]
What answers well whats the question?
4 0
3 years ago
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