Question

Suppose y is a positive integer.If x-(-y)=z will z be greater than x ?

Answer 1

Answer: Hello there!

we know that y is a positive integer, and we have the equation:

x - (-y) = z

we want to know if z > x

where we suppose that x and z are real numbers.

Now, the sign rule is the following:

(+)(+) = +

(-)(+) = -

(+)(-) = -

(-)(-) = +

Then the equation x - (-y) = z can be rewritten as:

x - (-y) = x + y = z

now let's isolate x

x = z - y

this means that the number x is equal to the number z decreased by the number y.

then the number z is bigger than the number x.

Answer 2

Answer:

Yes, z will be greater than x.

Step-by-step explanation:

Given expression is $x- (-y)=z \ for \ y \ is \ a \ positive \ integer.$

now let y = 2 and x = 1

Then, $x- (-y)=z \\1+2 = 3$

where $z> x$ i.e. 3 > 1

on simplifying the given  expression in terms of y

$y=z-x$

now suppose if x = 7 and z=3 then,

$y = (z-x) = (3-7) = (-4)$

which gives value of y in terms of negative integer which is not possible according to the given statement since y is a positive integer. Therefore, if y is a positive integer then  z will be greater than x.