Answer:
A, B and C
Step-by-step explanation:
Given any three side lengths of a right triangle, the longest side is the hypotenuse.
The side lengths of a right triangle must satisfy the <u>Pythagorean Theorem. </u>
Pythagorean Theorem: 
<u>Option A:</u> 

True
<u>Option B:</u> 2.5, 6, 6.5

<u>Option C:</u> 

Since all are true, the side lengths in Options A, B and C forms a right triangle,
Answer:
b
Step-by-step explanation:
b
Answer:
The inner function is
and the outer function is
.
The derivative of the function is
.
Step-by-step explanation:
A composite function can be written as
, where
and
are basic functions.
For the function
.
The inner function is the part we evaluate first. Frequently, we can identify the correct expression because it will appear within a grouping symbol one or more times in our composed function.
Here, we have
inside parentheses. So
is the inner function and the outer function is
.
The chain rule says:
![\frac{d}{dx}[f(g(x))]=f'(g(x))g'(x)](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%5Bf%28g%28x%29%29%5D%3Df%27%28g%28x%29%29g%27%28x%29)
It tells us how to differentiate composite functions.
The function
is the composition,
, of
outside function: 
inside function: 
The derivative of this is computed as

The derivative of the function is
.
Answer Standard form
Step-by-step explanation:
Answer:
Vel_jet_r = (464.645 mph) North + (35.35 mph) East
||Vel_jet_r|| = 465.993 mph
Step-by-step explanation:
We need to decompose the velocity of the wind into a component that can be added (or subtracted from the velocity of the jet)
The velocity of the jet
500 mph North
Velocity of the wind
50 mph SouthEast = 50 cos(45) East + 50 sin (45) South
South = - North
Vel_ wind = 50 cos(45) mph East - 50 sin (45) mph North
Vel _wind = 35.35 mph East - 35.35 mph North
This means that the resulting velocity of the jet is equal to
Vel_jet_r = (500 mph - 35.35 mph) North + 35.35 mph East
Vel_jet_r = (464.645 mph) North + (35.35 mph) East
An the jet has a magnitude velocity of
||Vel_jet_r|| = sqrt ((464.645 mph)^2 + (35.35 mph)^2)
||Vel_jet_r|| = 465.993 mph