Can you help me pl3s

Which side lengths form a right triangle? Choose all answers that apply: Choose all answers that apply: (Choice A) A 3, 6, \sqrt

dlinn [17]

Answer:

A, B and C

Step-by-step explanation:

Given any three side lengths of a right triangle, the longest side is the hypotenuse.

The side lengths of a right triangle must satisfy the Pythagorean Theorem.

Pythagorean Theorem: $Hypotenuse^2=Opposite^2+Adjacent^2$

Option A: $3, 6, \sqrt{45}$

$(\sqrt{45})^2=3^2+6^2\\45=36+9\\45=45$

True

Option B: 2.5, 6, 6.5

$6.5^2=6^2+2.5^2\\42.25=36+6.25\\42.25=42.25 (TRUE)$

Option C: $4, 8, \sqrt{80}$

$4, 8, \sqrt{80}\\( \sqrt{80})^2=4^2+8^2\\80=16+64\\80=80 (TRUE)$

Since all are true, the side lengths in Options A, B and C forms a right triangle,

4 0

3 years ago

(8x-4)+(17x-23)+(3x+17)=180

12345 [234]

Answer:

b

Step-by-step explanation:

b

7 0

3 years ago

For the composite function, identify an inside function and an outside function and write the derivative with respect to x of th

alexira [117]

Answer:

The inner function is $h(x)=4x^2 + 8$ and the outer function is $g(x)=3x^5$ .

The derivative of the function is $\frac{d}{dx}\left(3\left(4x^2+8\right)^5\right)=120x\left(4x^2+8\right)^4$ .

Step-by-step explanation:

A composite function can be written as $g(h(x))$ , where $h$ and $g$ are basic functions.

For the function $f(x)=3(4x^2+8)^5$ .

The inner function is the part we evaluate first. Frequently, we can identify the correct expression because it will appear within a grouping symbol one or more times in our composed function.

Here, we have $4x^2+8$ inside parentheses. So $h(x)=4x^2 + 8$ is the inner function and the outer function is $g(x)=3x^5$ .

The chain rule says:

$\frac{d}{dx}[f(g(x))]=f'(g(x))g'(x)$

It tells us how to differentiate composite functions.

The function $f(x)=3(4x^2+8)^5$ is the composition, $g(h(x))$ , of

outside function: $g(x)=3x^5$

inside function: $h(x)=4x^2 + 8$

The derivative of this is computed as

$\frac{d}{dx}\left(3\left(4x^2+8\right)^5\right)=3\frac{d}{dx}\left(\left(4x^2+8\right)^5\right)\\\\\mathrm{Apply\:the\:chain\:rule}:\quad \frac{df\left(u\right)}{dx}=\frac{df}{du}\cdot \frac{du}{dx}\\f=u^5,\:\:u=\left(4x^2+8\right)\\\\3\frac{d}{du}\left(u^5\right)\frac{d}{dx}\left(4x^2+8\right)\\\\3\cdot \:5\left(4x^2+8\right)^4\cdot \:8x\\\\120x\left(4x^2+8\right)^4$

The derivative of the function is $\frac{d}{dx}\left(3\left(4x^2+8\right)^5\right)=120x\left(4x^2+8\right)^4$ .

3 0

3 years ago

Help with this (explain in detail with the following vocab)

barxatty [35]

Answer Standard form

Step-by-step explanation:

5 0

3 years ago

Please help!!!! ASAP I’ll mark you as brainliest

KatRina [158]

Answer:

Vel_jet_r = (464.645 mph) North + (35.35 mph) East

||Vel_jet_r|| = 465.993 mph

Step-by-step explanation:

We need to decompose the velocity of the wind into a component that can be added (or subtracted from the velocity of the jet)

The velocity of the jet

500 mph North

Velocity of the wind

50 mph SouthEast = 50 cos(45) East + 50 sin (45) South

South = - North

Vel_ wind = 50 cos(45) mph East - 50 sin (45) mph North

Vel _wind = 35.35 mph East - 35.35 mph North

This means that the resulting velocity of the jet is equal to

Vel_jet_r = (500 mph - 35.35 mph) North + 35.35 mph East

Vel_jet_r = (464.645 mph) North + (35.35 mph) East

An the jet has a magnitude velocity of

||Vel_jet_r|| = sqrt ((464.645 mph)^2 + (35.35 mph)^2)

||Vel_jet_r|| = 465.993 mph

7 0

3 years ago