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3 years ago

Can someone help me plzz

Mathematics

1 answer:

Wittaler [7]3 years ago

5 0

Answer:3

Step-by-step explanation:

A. 2^4(4n) = 2^48

2^16n = 2^48

16n = 48

n = 3

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PLS HELP ASAP:Find all the missing elements:

adelina 88 [10]

Answer:

b ≈ 9.5, c ≈ 14.7

Step-by-step explanation:

Using the Sine rule in Δ ABC, that is

$\frac{a}{sinA}$ = $\frac{b}{sinB}$ , substitute values

$\frac{7}{sin23}$ = $\frac{b}{sin32}$ ( cross- multiply )

b × sin23° = 7 × sin32° ( divide both sides by sin23° )

b = $\frac{7sin32}{sin23}$ ≈ 9.5 ( to the nearest tenth )

Also

$\frac{a}{sinA}$ = $\frac{c}{sinC}$

$\frac{7}{sin23}$ = $\frac{c}{sin125}$ ( cross- multiply )

c × sin23° = 7 × sin125° ( divide both sides by sin23° )

c = $\frac{7sin125}{sin23}$ ≈ 14.7 ( to the nearest tenth )

3 0

3 years ago

A combination lock has 6 different numbers. You can use any number 0 - 9 in the combination, but each number can only be used ON

Zarrin [17]

There are 151,200 possible combinations. If you'd like an explanation of my answer, please let me know.

7 0

2 years ago

Given a school supply store sells pencils for $2, pens for $4, and markers for $5. Write an expression for the total cost of 3 p

soldi70 [24.7K]

Answer: 29

Step-by-step explanation:

3x2= 6

4x2=8

3x5=15

6+8+15= 29

hoped I helped you a bit! Good luck! :)

3 0

3 years ago

33. Suppose you were on a planet where the

tatyana61 [14]

Answer:

a) 3.675 m

b) 3.67m

Explanation:

We are given acceleration due to gravity on earth = $9.8ms^-2$

And on planet given = $2.0ms^-2$

A) Since the maximum jump height is given by the formula

$\mathrm{H}=\frac{\left(\mathrm{v} 0^{2} \times \sin 2 \emptyset\right)}{2 \mathrm{g}}$

Where H = max jump height,

v0 = velocity of jump,

Ø = angle of jump and

g = acceleration due to gravity

Considering velocity and angle in both cases

$\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 2}{\mathrm{g} 1}$

Where H1 = jump height on given planet,

H2 = jump height on earth = 0.75m (given)

g1 = 2.0 $ms^-2$ and

g2 = 9.8 $ms^-2$

Substituting these values we get H1 = 3.675m which is the required answer

B) Formula to find height of ball thrown is given by

$\mathrm{h}=(\mathrm{v} 0 * \mathrm{t})+\frac{\mathrm{a} *\left(t^{2}\right)}{2}$

which is due to projectile motion of ball

Now h = max height,

v0 = initial velocity = 0,

t = time of motion,

a = acceleration = g = acceleration due to gravity

Considering t = same on both places we can write

$\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 1}{\mathrm{g} 2}$

where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations

substituting h2 = 18m, g1 = 2.0 $ms^-2$ and g2 = 9.8 $ms^-2$

We get h1 = 3.67m which is the required height

6 0

3 years ago

ASAP What is the lateral area of this regular octagonal pyramid?? Explain your answer if you can plz thanks

Archy [21]

The lateral area would be 298.7 cm².

The lateral area is the area of all of the lateral faces of the pyramid. There are 8 triangles making up the lateral faces. Each has a base of 6.6. The formula for the area of a triangle is

A=1/2bh,

so we still need the height of the triangle.

The height of each lateral triangle is the slant height of the pyramid. The slant height of the pyramid forms a right triangle with the height of the pyramid and the "radius" as it were of the pyramid. Thus we use the Pythagorean theorem:

8²+8²=h²
64+64=h²
128=h²
√128=√(h²)
8√2 = h

Substituting this into our area formula we have:
A=1/2(6.6)(8√2)

We will go ahead and multiply this by 8, since there are 8 lateral faces:
LA=8(1/2)(6.6)(8√2)
LA = 298.7

3 0

3 years ago

Read 2 more answers

Can someone help me plzz​

Can someone help me plzz