Mass of iodine solid produced = 1.6 g
Iodine solid has a molecular formula : I2
Atomic mass of iodine = 126.904 g/mol
Therefore, molar mass of I2 solid = 2* 126.904 = 253.808 g/mol
Number of moles of a given substance is the ratio of its mass to the molar mass
# moles of I2 solid = mass of I2 solid/molar mass = 1.6 g/253.808 = 0.00630 moles
Hence, the # moles of iodine solid produced is 0.00630 moles
The weighted average of the nail in accordance with the given data is 11.176g.
<h3>How to calculate weighted average?</h3>
Weighted average is an arithmetic mean of values biased according to agreed weightings.
The weighted average of the nail in the image above can be calculated by multiplying the decimal abundance with the mass of the nail, then summed up as follows;
Weighted average = (decimal abundance × mass 1) + (decimal abundance × mass 2)
Weighted average = (0.12 × 3.3) + (0.88 × 12.25)
Weighted average = 0.396 + 10.78
Weighted average = 11.176g
Therefore, 11.176g is the weighted average of the nail
Learn more about weighted average at: brainly.com/question/28042295
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Radioisotopes are used to study chemical reactions because of the fact that they attach radioactive isotopes to certain atoms.<span> Tracer radioisotopes used to study chemical reactions in molecular structures by adding radioistopes to reactants and using the uptake compared to the original isotope. </span>
Answer:
HI (hydrogen iodide).
Explanation:
Hello,
In this case, since iodine is in group VIIA, it has seven valence electrons at its outer shell, which means that it only needs one bond to attain the octet. Moreover, since hydrogen has just one electron at its outer shell, one hydrogen turns out enough to obey the octet when hydrogen and iodine bond as shown below:
Therefore, the required formula is:
Which is hydrogen iodide.
Best regards.
Molar mass
Ca₃(PO₄)₂ = 310 g/mol
1 mole -------------------> 310 g
2.3x10⁻⁴ mole ---------> ?
m = 2.3x10⁻⁴ * 310 / 1
m = 0.0713 g
hope this helps!
