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3 years ago

Usealgebra tiles to represent polynomial.

1 answer:

3 0

To use algebra tiles to model an equation, we place the relevant number of variable rectangle tiles and number square tiles for the left side of the equation and for the right side of the equation. Then we play around with our tiles so that we end up with the rectangle tiles by themselves on one side

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MICHELLE TOSSES TWO COINS AND THEN DRAWS A CARD FROM A STANDARD DECK OF 52.

Marianna [84]

Answer:coins both a 50 50 chance and the cards have a 1 of a 52 chance of being drawn.

Step-by-step explanation: hope it helps and can you make me brainliest.

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7Bx%20%5Csqrt%7Bx%20%5Csqrt%7Bx%20%5Csqrt%7Bx....%7D%20%7D%20%7D%20%7D%20%20%3D%20%

andrey2020 [161]

First observe that if $a+b>0$ ,

$(a + b)^2 = a^2 + 2ab + b^2 \\\\ \implies a + b = \sqrt{a^2 + 2ab + b^2} = \sqrt{a^2 + ab + b(a + b)} \\\\ \implies a + b = \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b(a+b)}} \\\\ \implies a + b = \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b(a+b)}}} \\\\ \implies a + b = \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b \sqrt{\cdots}}}}$

Let $a=0$ and $b=x$ . It follows that

$a+b = x = \sqrt{x \sqrt{x \sqrt{x \sqrt{\cdots}}}}$

Now let $b=1$ , so $a^2+a=4x$ . Solving for $a$ ,

$a^2 + a - 4x = 0 \implies a = \dfrac{-1 + \sqrt{1+16x}}2$

which means

$a+b = \dfrac{1 + \sqrt{1+16x}}2 = \sqrt{4x + \sqrt{4x + \sqrt{4x + \sqrt{\cdots}}}}$

Now solve for $x$ .

$x = \dfrac{1 + \sqrt{1 + 16x}}2 \\\\ 2x = 1 + \sqrt{1 + 16x} \\\\ 2x - 1 = \sqrt{1 + 16x} \\\\ (2x-1)^2 = \left(\sqrt{1 + 16x}\right)^2$

(note that we assume $2x-1\ge0$ )

$4x^2 - 4x + 1 = 1 + 16x \\\\ 4x^2 - 20x = 0 \\\\ 4x (x - 5) = 0 \\\\ 4x = 0 \text{ or } x - 5 = 0 \\\\ \implies x = 0 \text{ or } \boxed{x = 5}$

(we omit $x=0$ since $2\cdot0-1=-1\ge0$ is not true)

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2 years ago

What is the solution to the equation?c/35=3/7

MaRussiya [10]

Answer:C=15

Step-by-step explanation:

Just do math

7 0

3 years ago

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Use the given graph to determine the limit, if it exists. A coordinate graph is shown with a downward sloped line crossing the y

vesna_86 [32]

For the limit approaching 3 from the right, you want to follow the line to the right of x = 3. From the graph you're describing it sounds like that's y = -3. $\lim_{x \to 3} f(x)=-3$

The RHS limit is -3 even though f(3) = 7

4 0

3 years ago

Simplify <br> 12a-(4b+4a)-b

lara31 [8.8K]

12a-(4b+4a)-b
12a-4b-4a-b
=> 8a-5b

8 0

4 years ago

Read 2 more answers

Usealgebra tiles to represent polynomial.​

Usealgebra tiles to represent polynomial.