Usealgebra tiles to represent polynomial.

1 answer:

3 0

To use algebra tiles to model an equation, we place the relevant number of variable rectangle tiles and number square tiles for the left side of the equation and for the right side of the equation. Then we play around with our tiles so that we end up with the rectangle tiles by themselves on one side

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9.Solve. 5a - 10 = 4a + 8Immersive Reader

aivan3 [116]

5a-10=4a+8

5a-4a=8+10

a=18

3 0

2 years ago

Select Proportional or Not Proportional to correctly classify each pair of ratios.

Paul [167]

Answer:

Not Proportional

Step-by-step explanation:

6 0

3 years ago

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You are setting up a zip line in your yard. You map out your yard in a coordinate plane. An equation of the line representing th

neonofarm [45]

Answer:

Distance is 6.7units to the nearest tenth.

Explanation:

To solve this problem, we the distance formula. And this is given as:

$D = \frac{|a x + b y + c|}{\sqrt{a^2 + b^2}}$

We were given the equation:

y = 2 x + 4

This can also be rewritten as:

y – 2 x – 4 = 0.

Therefore, a = -2, b = 1 and c = -4

Also, we were given the points:

(x, y) = (–4, 11)

Making use of the above formula for distance, we have:

$D = \frac{|-2\times -4 + 1\times 11 + -4|}{\sqrt{-2^2 + -4^2}}$

$D = \frac{15}{\sqrt{5}}$

D = 6.7units (to the nearest tenth)

8 0

2 years ago

Which expression is equivalent to b^m x b^n? A. b^m+n B. b^m-n C. b^mx n D. b^m/n

noname [10]

The formula for multiplying exponents are such below.

(b^m)^n = b^mn
b^m/b^n=b^(m-n)
b^m x b^n=b^(m+n)

4 0

3 years ago

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An advertising company is designing a new logo that consists of a shaded triangle inside a parallelogram.What is the area, in sq

tatyana61 [14]

<h2>Explanation:</h2><h2 />

The complete question is shown in the figure below. As you can see one square units is well shown in the graph. So we can conclude that the distance between two consecutive points is 1 unit. If so, then we can calculate the area of the parallelogram as follows:

$A=b\times h \\ \\ A:Area \\ \\ b:Base \\ \\ h:Height \\ \\ \\ CB=b \\ \\ AB=h$