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3 years ago

What is the value of x squared + 2 x y / 2 * W + 3 * z for w=2, x=5, y=8 and z=3

Mathematics

1 answer:

insens350 [35]3 years ago

4 0

Answer: 114

Step-by-step explanation:

Plug in the numbers. 5*5+2*5*8/2*2+3*3=25+80+9=114

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12) Given that p is an integer, q = -12 and the quotient of р 9 is -3, find p. A) -36 B) -4 C) 4 D) 36

dolphi86 [110]

D) 36

So q is equal to -12 and P divided by Q will be equal to -3
but since you know Q you replace it with -12 and now it's gonna be P divided by -12 equal to -3
move -12 to the other side by multiplying -12 to both sides so you cancel out the -12 under P and you get to isolate P
-3 times -12 will be +36 because the two negative signs cancel out

4 0

2 years ago

Need help with math problem please

Zigmanuir [339]

P= -8, 3
q= -3, 3
r= 1, 6
s= -4, 6

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3 years ago

Identity the congruence statement for the triangles below.

GalinKa [24]

<u>Answer:</u>

Triangle HMK≅Triangle ILJ

<u>Explanation:</u>

Two triangles are congruent if they have the same sides and the same size. This means they have the same shape and size, regardless of their position or orientation.

If we want to verify if two triangles are congruent, they must fulfill some conditions:

a) Two triangles are congruent if their three sides are respectively equal

b) Two triangles are congruent if two of their sides and the angle between them are respectively of equal length.

c) Two triangles are congruent if they have a congruent side and the angles with vertex at the ends of that side are also congruent.

d) Two triangles are congruent if they have two sides respectively congruent and the angles opposite the greater of the sides are also congruent

According to these criteria, Triangle HMK≅Triangle ILJ

5 0

4 years ago

Three numbers in the interval $\left[0,1\right]$ are chosen independently and at random. What is the probability that the chosen

k0ka [10]

Let $a,b,c$ be the randomly selected lengths. Without loss of generality, suppose $a[tex]P(A + B \ge C) = P(A + B - C \ge 0)$

where $A,B,C$ are independent random variables with the same uniform distribution on [0, 1].

By their mutual independence, we have

$P(A=a,B=b,C=c) = P(A=a) \times P(B=b) \times P(C=c)$

so that the joint density function is

$P(A=a,B=b,C=c) = \begin{cases}1 & \text{if }(a,b,c)\in[0,1]^3 \\ 0 & \text{otherwise}\end{cases}$

where $[0,1]^3=[0,1]\times[0,1]\times[0,1]$ is the cube with vertices at (0, 0, 0) and (1, 1, 1).

Consider the plane

$a + b - c = 0$

with $(a,b,c)\in\Bbb R^3$ . This plane passes through (0, 0, 0), (1, 0, 1), and (0, 1, 1), and thus splits up the cube into one tetrahedral region above the plane and the rest of the cube under it. (see attached plot)

The point (0, 0, 1) (the vertex of the cube above the plane) does not belong the region $a+b-c\ge0$ , since $0+0-1=-1$ . So the probability we want is the volume of the bottom "half" of the cube. We could integrate the joint density over this set, but integrating over the complement is simpler since it's a tetrahedron.

Then we have

$\displaystyle P(A+B-C\ge0) = 1 - P(A+B-C < 0) \\\\ ~~~~~~~~ = 1 - \int_0^1\int_0^{1-a}\int_{a+b}^1 P(A=a,B=b,C=c) \, dc\,db\,da \\\\ ~~~~~~~~ = 1 - \int_0^1 \int_0^{1-a} (1 - a - b) \, db \, da \\\\ ~~~~~~~~ = 1 - \int_0^1 \frac{(1-a)^2}2\,da \\\\ ~~~~~~~~ = 1 - \frac16 = \boxed{\frac56}$

5 0

2 years ago

In parallelogram ABCD, AC=87.5 and BC=52.5. If ABCD is a rectangle, find AB.

igor_vitrenko [27]

We can do this using Pythagorus,,,
87.5*2 - 52.5*2 = AB*2
4900 = AB*2
70 = AB

3 0

3 years ago

What is the value of x squared + 2 x y / 2 * W + 3 * z for w=2, x=5, y=8 and z=3​

What is the value of x squared + 2 x y / 2 * W + 3 * z for w=2, x=5, y=8 and z=3