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Marysya12 [62]
3 years ago
5

A group of friends went fishing. They each caught 20 fish but not all of them were keepers. Which person was able to keep 3/5 of

the fish that he or she caught?
Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
8 0

Answer:

Those who were able to keep 12 fishes

Step-by-step explanation:

Given

Total = 20 (each)

Required

Which was able to keep 3/5

First, we need to calculate 3/5 of the total number of fishes

Fish = 3/5 * 20

Fish = (3 * 20)/5

Fish = 60/5

Fish = 12

From the calculation above, only those who keep 12 of the 20 fishes were able to keep 3/5 of their fishes

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olasank [31]

Answer:

(g)x divided by 12/4

Step-by-step explanation:

6 0
2 years ago
An aircraft factory manufactures airplane engines. The unit cost C (the cost in dollars to make each airplane engine) depends on
butalik [34]

Answer:

90 engines must be made to minimize the unit cost.

Step-by-step explanation:

Vertex of a quadratic function:

Suppose we have a quadratic function in the following format:

f(x) = ax^{2} + bx + c

It's vertex is the point (x_{v}, y_{v})

In which

x_{v} = -\frac{b}{2a}

y_{v} = -\frac{\Delta}{4a}

Where

\Delta = b^2-4ac

If a>0, the minimum value of the function will happen for x = x_v

C(x)=x²-180x+20,482

This means that a = 1, b = -180, c = 20482

How many engines must be made to minimize the unit cost?

x value of the vertex. So

x_{v} = -\frac{b}{2a} = -\frac{-180}{2(1)} = 90

90 engines must be made to minimize the unit cost.

3 0
2 years ago
The times of the runners in a marathon are normally distributed, with a mean of 3 hours and 50 minutes and a standard deviation
serious [3.7K]

The probability that a randomly selected runner has a time less than or equal to 3 hours and 20 minutes is 0.16 or 16%.

<h3>What is normally distributed data?</h3>

Normally distributed data is the distribution of probability which is symmetric about the mean.

The mean of the data is the average value of the given data.

The standard deviation of the data is the half of the difference of the highest value and mean of the data set.

The times of the runners in a marathon are normally distributed, with

  • Mean of 3 hours and 50 minutes
  • Standard deviation of 30 minutes.

Refere the probabiliity table attached below. The probability of Z being inside the 1 Standard daviation of mean is 0.84.

The probability of runner selected with time less than or equal to 3 hours and 20 minutes,

P=1-0.84\\P=0.16

Thus, the probability that a randomly selected runner has a time less than or equal to 3 hours and 20 minutes is 0.16 or 16%.

Learn more about the normally distributed data here;

brainly.com/question/6587992

4 0
1 year ago
The following set of coordinates most specifically represents which figure? (−5, 6), (−1, 8), (3, 6), (−1, 4) (6 points) Paralle
Vladimir [108]

Answer:

Rhombus

Step-by-step explanation:

The given points are A(−5, 6), B(−1, 8), C(3, 6), D(−1, 4).

We use the distance formula to find the length of AB.

|AB|=\sqrt{(-1--5)^2+(8-6)^2}

|AB|=\sqrt{16+4}

|AB|=\sqrt{20}

The length of AD is

|AD|=\sqrt{(-1--5)^2+(6-4)^2}

|AD|=\sqrt{16+4}

|AD|=\sqrt{20}

The length of BC is:

|BC|=\sqrt{(-1-3)^2+(8-6)^2}

|BC|=\sqrt{16+4}

|BC|=\sqrt{20}

The length of CD is

|CD|=\sqrt{(-1-3)^2+(6-4)^2}

|CD|=\sqrt{16+4}

|CD|=\sqrt{20}

Since all sides are congruent the quadrilateral could be a rhombus or a square.

Slope of AB=\frac{8-6}{-1--5}=\frac{1}{2}

Slope of BC =\frac{8-6}{-1-3}=-\frac{1}{2}

Since the slopes of the adjacent sides are not negative reciprocals of each other, the quadrilateral cannot be  a square. It is a rhombus

7 0
3 years ago
Read 2 more answers
Evaluate each function.<br> 14) g(x)= 3x² - 1; Find g(-3)
adelina 88 [10]

g(x) =3x^2 -1\\\\g(-3)=3(-3)^2 -1 \\ \\~~~~~~~~~=3(9) -1 \\\\~~~~~~~~~=27-1\\\\~~~~~~~~~=26

5 0
2 years ago
Read 2 more answers
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